Answer:
1) y=⅚x -2⅓
2) y=8/3x -5
Step-by-step explanation:
<u>Point-slope form:</u>
y=mx+c, where m is the gradient and c is the y-intercept.
Parallel lines have the same gradient.
Gradient of given line= 
Thus, m=⅚
Susbt. m=⅚ into the equation,
y= ⅚x +c
Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.
When x=4, y=1,
1= ⅚(4) +c
Thus the equation of the line is 
.
The gradients of perpendicular lines= -1.
Gradient of given line= -⅜
-⅜(gradient of line)= -1
gradient of line
= -1 ÷ (-⅜)
= -1 ×(-8/3)
= 
When x=3, y=3,
Thus the equation of the line is 
.
Answer:
192
Step-by-step explanation:
6(3+5)4
3+5=8
6(8)4
6x8=48
48x4=192
Answer:
Step-by-step explanation:
<u>Complete the square</u>
<u />
Answer:
1.5
Step-by-step explanation:
because if u divide 6 by 4 that will equal 1.5
Answer:
Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.
Step-by-step explanation:
Given , Josiah owns a food truck that sells tacos and burritos.
He sells each burritos for $7.50. If 79 burritos were sold.
Then the price of 79 burritos is $(7.50×79) =$592.50
Let x tacos were sold.
He sells each tacos for $5.
Then the price of x tacos is = $(x × 5)=$5x
Also given that Josiah must sell a minimum of $930 worth of tacos and burritos.
Therefore,
5x+592.50≥ 930
⇔5x≥930-592.50
⇔5x≥337.5
⇔x≥67.5
But he only has enough supplies to make 149 tacos or burrito.
He already sold 79 burrito.
So, remain space for tacos is = (149-79) = 70
So,67.5≤x≤70
∴x = 68 or 69 or 70
Therefore Josiah must sell 68 or 69 or 70 tacos in order to meet the requirement.
