Answer:
Step-by-step explanation:
y∞x
then
y=kx (with k as constant)
y=5 when x=8
⇒Putting this in the first equation
⇒5=k×8
⇒k=5/8
Now
y=? when x=64
Putting x=64 in the first equation
y=kx
⇒y=(5/8)×64
We get
y=40
Hope u understand
1500(1+0.04)^3 = 1687.30
1687.30(1+0.05) = 1771.67 to the nearest pound: 1772
The answer is x=3
1x=3 so that means that one x is the same as 3
Answer:
f(-3) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = -1x - 4
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function f(x)]: f(-3) = -1(-3) - 4
- Multiply: f(-3) = 3 - 4
- Subtract: f(-3) = -1
Answer:
<h2>
0</h2>
Step-by-step explanation:
Given,

Now, let's find the value of 9x + 6

plug the value of X

Multiplying a positive and negative equals a negative


Reduce the number with Greatest Common Factor 3

Multiply the numbers

The sum of two opposites equals 0

Hope this helps..
best regards!!