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3 years ago

If you lend $500.00 to your brother, what is your opportunity cost?

1 answer:

8 0

Opportunity cost is the value of the next best alternative when you make a decision; it's what you give up. Understanding opportunity cost allows you to make decisions, knowing both what you are getting and what you are giving up. in the above case of lending of $500.00 to your brothers is What you want most costing $500.

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Ill mark you brainlist plz help if you put something random I will report you!

Tresset [83]

Answer:

Step-by-step explanation:

180-145=35

5 0

3 years ago

Read 2 more answers

A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable

Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.3$ .

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066$

$P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014$

$P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002$

$P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024$

$P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002$

$P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0$

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082$

0.0082 = 0.82% probability that he will pass

6 0

3 years ago

Find 3/5 - 1/4 a 4/9 b 1/2 c 2 d 7/20

Lubov Fominskaja [6]

Answer:

7/20

Step-by-step explanation:

Hope this helped!

7 0

3 years ago

Read 2 more answers

Consider a continuous random variable x, which is uniformly distributed between 65 and 85. The probability of x taking on a valu

madam [21]

We will see that the probability of x taking on a value between 75 to 90 is P = 0.5

<h3>How to get the probability?</h3>

We know that x is a continuous random variable uniformly distributed between 65 and 85.

This means that the probability that x value y in the range is such that:

1 = P(y)*(85 - 65) = P(y)*20

1/20 = P(y).

Now, the probability of x taking a value between 75 and 85 is:

P(75 to 85) = (1/20)*(85 - 75) = 10/20 = 0.5

And the probability between 85 and 90 is zero (because the maximum value that x can take is 85, so this part does not affect).

Then we conclude that the probability of x taking a value between 75 to 90 is:

P(75 to 90) = P(75 to 85) + P(85 to 90) = 0.5 + 0 = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

5 0

2 years ago

A 5 poundbag of peanuts costs $9.30. It's going to be divided into 3/4 pound bags. How much will one bag cost?

dsp73

9.3/5 means that each pound is $1.86.

3/4 ($1.86) =$1.395 or $1.40 for 3/4 pound of peanuts. Hope that helps. :)

7 0

3 years ago