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Tema [17]
3 years ago
14

Hi ik no one would have any hope in my friend basically he got super sick .. and he said nothing would make him feel happier if

yall don't help him with his subs .. his Yt is 999 Trendy if you do this i would give brainliest and appreciate you a lot :) - tty
Mathematics
1 answer:
Dovator [93]3 years ago
8 0

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

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Write a paragraph proof.<br><br> Given: ∠T and ∠V are right angles.<br><br> Prove: ∆TUW ∆VWU
Veseljchak [2.6K]

Step-by-step explanation:

in ∆TUW & ∆VWU

∠UTW = ∠UVW (data / given)

WU = WU (common sides) ∠TWU = ∠VUW (TW//UV alternate∠ )

so ∆TUW & ∆VWU are congruent

8 0
2 years ago
Read 2 more answers
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
1 year ago
12. The average bowling score of the 5-member in Regional High School bowling team is 128. If all the members of the team get th
mel-nik [20]

Answer:

C

Step-by-step explanation:

The average is the total of the scores divided by 5.  

128 x 5 Gives us the total scores of 640.  I know that one bowler had a score of 160.  I will subtract that from the total of 640.  640-160 = 480.  Since the 4 bowlers left, all had the same score, I will divide 480 by 4 to get 120

3 0
2 years ago
Given tanθ = 8, find csc(θ)
In-s [12.5K]
Cosecθ=sq.rt of 65/8. hope it will help you
4 0
2 years ago
Read 2 more answers
Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3
yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
1 year ago
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