Answer:
762 days
Step-by-step explanation:
Given

Let the rate be R.
So the rate change with time is represented as:

So:

To get the number of insects between day 0 and day 3, we need to integrate dR and set the bounds to 0 and 3
i.e.
becomes


Integrate
![R = 200t + \frac{10t^2}{2} + \frac{13t^3}{3} [3,0]](https://tex.z-dn.net/?f=R%20%3D%20200t%20%2B%20%5Cfrac%7B10t%5E2%7D%7B2%7D%20%2B%20%5Cfrac%7B13t%5E3%7D%7B3%7D%20%5B3%2C0%5D)
Solve for R by substituting 0 and 3 for t





<em>The population of insect between the required interval is 762</em>
Answer:
they're equal
Step-by-step explanation:
Answer:
3x + 3 = -2x + 3
3x + 2x = 3 - 3
5x = 0
x =0.
So y = 3(0) + 3 = 3.
Step-by-step explanation:
Answer:
the pattern is going in the form of 1³ , 2³ , 3³ , 4³
therefore next term should be 5³ which is equal to 125. So <u>the missing term is 125 </u>
I hope you got that.
By : Modern Einstein
I'm assuming the equation is x^3 = 216 or

(both mean the same thing)
If so, then the solution to x^3 = 216 is
x = 6
<span>We can find this by taking the cube root of both sides
</span>x^3 = 216
x = 216^(1/3) .... 1/3 power means cube root
x = 6
Checking the answer:
x^3 = 216
6^3 = 216
6*6*6 = 216
216 = 216
Answer is confirmed
So once again
the answer is x = 6. This is assuming the initial assumption made at the top of the problem holds up.