2.4cm and 6.5cm what is the length of this equation

Bob,Cal,and Pete each made a stack of baseball cards.Bob's stack was 0.2 meter high.Cal's stack was 0.24 meter high.Pete's stack

AlekseyPX

Answer:

0.24 > 0.18

Step-by-step explanation:

Given that,

Bob's stack = 0.2m

Cal's stack = 0.24m

Pete's stack = 0.18m

To find?

A number sentence.

A simple sentence is a string/collection of words that contain a subject and a verb whereas a number sentence is a sentence that consist of mathematical operation like +, -, /, * together with an equality such as =, <, >, and like a sentence it also tell a fact.

So, the number sentence that compares cal's stack of cards to Pete's stack is

6 0

3 years ago

Read 2 more answers

A barge is carrying 342,000 pounds of concrete blocks. How much weight is this in tons?

Anton [14]

171 ask google if u think im wrong

171 tons.

4 0

3 years ago

PLEASE ANSWER 8TH GRADE MATH QUESTION!

Alina [70]

Wanna show a picture first

4 0

3 years ago

PLSSS HELP IMMEDIATELY!!!!! i’ll give brainiest, i’m not giving brainiest if u leave a link tho. (pls check whole picture!!) a

emmainna [20.7K]

Answer:

(0, 1)

Step-by-step explanation:

All other choices do not match the two possible vertices of the square.

4 0

3 years ago

An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of

Helga [31]

Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

Volume of Cone = $\pi r^{2} \frac{h}{3}$

a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

$r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm$

We will now find the volume of the cone.

Volume of cone $\pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}$

We know the density of ice is 0.93 grams per $1cm^{3}$

$1cm^{3} =0.93g\\\frac{168175\pi }{24} cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g$ (Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = $\pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}$

Volume of cone being melted = New Volume - Original volume

= $\frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}$

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = $\pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}$

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = $5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}$

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= $\frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}$

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

4 0

2 years ago