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12345 [234]
3 years ago
6

7.

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Answers:

  • prime number = {2,3,5}
  • composite number = {4,6}
  • number less than four = {1,2,3}
  • number more than or equal to three = {3,4,5,6}

====================================================

Explanation:

The list of all possible outcomes on a single standard die is {1,2,3,4,5,6}. The curly braces indicate set notation.

A prime number is a number where its only factors are 1 and itself. The value 1 is not prime, and it's not composite either.

Something like 3 is prime because its only factors are 1 and 3. Something like 4 is composite because 4 = 2*2. A composite value has factors other than 1 and itself.

Parts (iii) and (iv) are fairly straight forward. You simply list items less than four for part (iii) and you list items that are three or greater for part (iv).

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Solve the system of equations.<br> y=7x<br> y=2x + 20<br><br> x=?<br> y=?
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3 years ago
Serenity invested $2,400 in an account paying an interest rate of 3.4% compounded
Alisiya [41]

Answer:

It would take 5.9 years to the nearest tenth of a year

Step-by-step explanation:

The formula of the compound continuously interest is A = Pe^{rt} , where

  • A is the value of the account in t years
  • P is the principal initially invested
  • e is the base of a natural logarithm
  • r is the rate of interest in decimal

∵ Serenity invested $2,400 in an account

∴ P = 2400

∵ The account paying an interest rate of 3.4%, compounded continuously

∴ r = 3.4% ⇒ divide it by 100 to change it to decimal

∴ r = 3.4 ÷ 100 = 0.034

∵ The value of the account reached to $2,930

∴ A = 2930

→ Substitute these values in the formula above to find t

∵ 2930 = 2400e^{0.034t}

→ Divide both sides by 2400

∴ \frac{293}{240} = e^{0.034t}

→ Insert ㏑ in both sides

∴ ㏑(\frac{293}{240}) = ㏑(e^{0.034t})

→ Remember ㏑(e^{n}) = n

∴ ㏑(\frac{293}{240}) = 0.034t

→ Divide both sides by 0.034 to find t

∴ 5.868637814 = t

→ Round it to the nearest tenth of a year

∴ t = 5.9 years

∴ It would take 5.9 years to the nearest tenth of a year

8 0
2 years ago
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