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2 years ago

10

Compare the motion of the boy and the man. Who was going faster? Was their acceleration about the same? Who had more frictional

force? What might have caused the difference in frictional force?

1 answer:

aivan3 [116]2 years ago

5 0

Answer:

can you make the question clearer old?

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Which statement about distance is correct

zhuklara [117]

Answer:

idk

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3 years ago

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natima [27]

Answer:

8

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3 years ago

Ac=4 bx=y+4 what is the value of y

Kitty [74]

Ac=4 bx=y+4 doesn't make sense. Perhaps you meant <span>Ac-4bx=y+4. If this is not correct, ensure that you have copied down the original problem correctly.

</span>To solve Ac-4bx=y+4 for y, subtract 4 from both sides of this equation. You'll get:

Ac-4bx-4 = y+4 - 4, or y = ac-4bx - 4.

6 0

3 years ago

Suppose that profit for a particular product is calculated using the linear equation: Profit = 20S + 3D. Which of the following

uranmaximum [27]

Answer:

b. S = 405, D = 0

Step-by-step explanation:

We have been given that profit for a particular product is calculated using the linear equation: $\text{Profit}=20S+3D$ . We are asked to choose the combinations of S and D that would yield a maximum profit.

To solve our given problem, we will substitute given values of S and D in the profit function one by one.

a. S = 0, D = 0

$\text{Profit}=20S+3D$

$\text{Profit}=20(0)+3(0)$

$\text{Profit}=0$

b. S = 405, D = 0

$\text{Profit}=20S+3D$

$\text{Profit}=20(405)+3(0)$

$\text{Profit}=8100+0$

$\text{Profit}=8100$

c. S = 0, D = 299

$\text{Profit}=20S+3D$

$\text{Profit}=20(0)+3(299)$

$\text{Profit}=0+897$

$\text{Profit}=897$

d. S = 182, D = 145

$\text{Profit}=20S+3D$

$\text{Profit}=20(182)+3(145)$

$\text{Profit}=3640+435$

$\text{Profit}=4075$

Since the combination S = 405, D = 0 gives the maximum profit ($8100), therefore, option 'b' is the correct choice.

7 0

3 years ago

For f(x) = 2x +1 and g(x) = x^2-7, find (f/g) (x)

Rashid [163]

the answer is (f/g)(x) = 2(x^2 - 7) + 1
= 2x^2 - 14 + 1
= 2x^2 - 13

5 0

3 years ago