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IrinaK [193]
3 years ago
7

To make the chocolate shake, Dona added 40 mL of chocolate syrup, 200 mL of milk, and 400 mL of water. How much milk, in liters,

would be required if she uses 450 mL of water? a. 0.225 c. 225 b. 0.45 d. 0.05
Mathematics
1 answer:
kykrilka [37]3 years ago
4 0

Answer:

Step-by-step explanation:

Ratio of water and milk are in direct proportion

200 : 400 :: x : 450

Product of means =  product of extremes

       400 * x =  200 * 450

                 x = \frac{200*450}{400}

                    = 225 ml of milk

   1 ml = 1/1000 l

225 ml = 225 ÷ 1000 = 0.225 l

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The graph shows how the mass of copper
Alex777 [14]

Answer: 8 1/4g/cm³

Step-by-step explanation:

Given the graph :

The rate of change in the mass of copper with respect to volume :

To obtain this, we find the slope or gradient of the graph:

Gradient = Δy / Δx = (y2 - y1) / (x2 - x1)

Drawing a right angled triangle on the anybpart of the line of best fit:

y2 = 40 ; x2 = 4.75 ; y1 = 16 ; x1 = 2

(y2 - y1) / (x2 - x1)

= (40 -16) / (4.75 - 2)

= 24 / 2.75

= 2400/275

= 8.727 g/cm^3

Due to unit and graph scale,, the slope is closest to 8 1/4g/cm³

6 0
3 years ago
What is the relationship between 1's in 911,147,835
Lelu [443]
The relationship between 1’s in the value of 911, 147, 835 shows their numerical order in the number. In which to further elaborate we shall break down the number into its expanded form and word form: <span><span>1. </span>900, 000, 000 = nine hundred million</span> 10, 000, 000 = ten million 1, 000, 000 = one million 100, 000 = one hundred thousand 40, 000 = forty thousand 7, 000 = seven thousand 800 = eight hundred 30 = thirty 5 = five <span><span>2. </span><span> Nine hundred eleven million one hundred forty-seven thousand eight hundred and thirty five. </span></span>



4 0
3 years ago
How does the unit circle allow the trigonometric functions to be defined for all real numbers instead of just for acute angles?
Molodets [167]

Every point in the unit circle is identified either by its coordinates (x,y) or by the angle it forms with the x-axis, \alpha.

The trigonometric functions associate with every angle \alpha and the correspondant (x,y) coordinates the two values

\cos(\alpha)=x,\quad\sin(\alpha)=y

This procedure can be done for every angle \alpha, so you don't have to work with acute angles only.

8 0
3 years ago
Ruby has a bird feeder which is visited by an average of 13 birds every 2 hours during daylight hours. What is the probability t
zalisa [80]

Answer:

62.93%

Step-by-step explanation:

We have to solve it by a Poisson distribution, where:

p (x = n) = e ^ (- l) * l ^ (x) / x!

Where he would come being the number of birds that there would be in 40 minutes, we know that in 2 hours, that is 120 minutes there are 13, therefore in 40 there would be:

l = 13 * 40/120

l = 4,333

Now, we have p (x> 3) and that is equal to:

p (x> 3) = 1 - p (x <= 3)

So, we calculate the probability from 0 to 3:

 p (x = 0) = 2.72 ^ (- 4.33) * 4.33 ^ (0) / 0! = 0.01313

p (x = 1) = 2.72 ^ (- 4.33) * 4.33 ^ (1) / 1! = 0.0568

p (x = 2) = 2.72 ^ (- 4.33) * 4.33 ^ (2) / 2! = 0.12310

p (x = 3) = 2.72 ^ (- 4.33) * 4.33 ^ (3) / 3! = 0.17767

If we add each one:

0.01313 + 0.0568 + 0.12310 + 0.17767 = 0.3707

replacing:

p (x> 3) = 1 - 0.3707

p (x> 3) = 0.6293

Which means that the probability is 62.93%

5 0
3 years ago
What is an example of when you would want consistent data and, therefore, a small standard deviation?
steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

\bar X=\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

8 0
3 years ago
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