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antiseptic1488 [7]

3 years ago

14

When a low-mass star runs out of helium to fuse into carbon, what will it do?

1 answer:

Andrei [34K]3 years ago

5 0

A false dalse true true false and thats a;ll i know

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Show that the equation below is dimensionally correct. y=vo t + 1/2 a t2 . ( where a is acceleration , v is the velocity and y i

mojhsa [17]

$y$ has units of m, $v_0$ has units of m/s, $t$ has units of s, and $a$ has units of m/s^2. The constant 1/2 does not have units.

Hence, the first term on the right has units of: m/s *s = m
While the second term on the right has units of: m/s^2 * s * s = m

Thus, the equation is dimensionally correct.

8 0

3 years ago

Unit of energy density of electric field is a) NC-3 b) JC-3 c) Jm-3 d)JF

erik [133]

Answer:

the answer is c

8 0

4 years ago

Read 2 more answers

12. One object has half the mass of another object. The first object also has half the ---.

Tanya [424]

The first object also has half the inertia.

Answer: Option A

<u>Explanation:</u>

Inertia is the tendency of an object to remain in its state. It resists the change in the state of object due to any external forces. So the inertia is the property of an object to resists the change in its state due to any kind of external force. Thus as the mass decreases, the central mass of inertia of the object will also decrease as both are directly proportional to each other.

3 0

3 years ago

The gravitational force between two asteroids is 2.59 × 10 (exponent)-6 N. The centers of mass are 2000 meters away and their ma

makkiz [27]

Answer:

$2.79 \times 10^5 \ \text{kg}$

Explanation:

Newton's Law of Universal Gravitation:

$$F= G\frac{m_1 m_2}{r^2}$
F = force of gravity (N)
G = gravitational constant $(6.67 \times 10^-^1^1 \ N\frac{m^2}{kg^2})$
$m_1$ = mass of Object 1 (kg)
$m_2$ = mass of Object 2 (kg)
r = distance between the center of mass (m)

Let's convert our given information to scientific notation:

$2000 \ m \rightarrow 2.0 \times 10^3 \ m$

Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:

$2.59 \times 10^-^6 $\ N = 6.67 \times 10^-^1^1 \ N \frac{m^2}{kg^2} \times \frac{m_1 m_2}{(2.0 \times 10^3 \ m)^2}$

Remove the units for better readability.

$2.59 \times 10^-^6=6.67 \times 10^-^1^1 \frac{m_1m_2}{(2.0 \times 10^3)^2}$

Divide both sides of the equation by the gravitational constant G.

$\frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{(2.0 \times 10^3)^2}$

Distribute the power of 2 inside the parentheses.

$\frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{2.0 \times 10^6}$

If we evaluate the left side of the equation, we get:

$3.88305847 \times 10^4 = \frac{m_1m_2}{2.0 \times 10^6}$

Multiply both sides of the equation by r.

$7.76611694 \times 10^1^0= m_1m_2$

In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite $m_1m_2$ as $m^2$ .

$7.76611694 \times 10^1^0= m^2$

Square root both sides of the equation.

$m=\sqrt{7.76611694 \times 10^1^0}$

$m=2.78677536 \times 10^5$
$m=2.79 \times 10^5$

Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.

3 0

3 years ago

Explain why compressional waves are unable to move through a vacuum

Aleonysh [2.5K]

Compressional waves are mechanical.mechanical waves require a medium to travel. in a vacuum, there is no matter, so the waves cannot travel

7 0

3 years ago