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svet-max [94.6K]
3 years ago
8

what are 3 CHEMICAL REACTIONS that you personally observed over the last 2 weeks. You should only include chemical reactions tha

t you see every day around you, not chemical reactions that would occur in a lab. I need answers for my science project pls! Will upvote,mark as brainly,and give thanks!
Physics
1 answer:
Allisa [31]3 years ago
6 0

1).  I started up my car.  Gasoline was spritzed into the cylinders, mixed with air, and then exploded with an electrical spark.  As the gasoline vapor instantly burned in the air, several new things were formed that weren't there before, like carbon dioxide, carbon monoxide, water, and oxides of nitrogen.

2).  I left my dinner on the stove a little too long, and it got a layer of crunchy crackly sooty carbon on the bottom. That part of it didn't taste too good.  This isn't exactly something that happens every day, but more often than I'd like it too.

3).  All day, every day, and all night, every night, about 10 or 20 times every minute, I pull air into my lungs.  I keep it there for a while, then I blow it out and pull in some fresh stuff.  The air I blow out has less oxygen and more carbon dioxide in it than it had when I pulled it in.  That's because of the hundreds of chemical reactions going on inside my body, to keep me alive and functioning.  I hope these keep going on for many many more days in the future.  

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Are the two displacements equal? Explain your answer.
Sergeu [11.5K]
From the information given in the drawing, it's not possible
to tell whether the displacements are equal, because we
don't know what the vectors represent.

If the vectors are distances, then the displacements are not
equal, because the distance between the start and end points
are not equal.

If the vectors are speeds, then they don't tell us anything about
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7 0
3 years ago
Read 2 more answers
You drive on Interstate 10 from San Antonio to Houston, half the time at 54 km/h and the other half at 118 km/h. On the way back
Irina-Kira [14]

Answer:

Average speed: 86 km/h

Explanation:

Driving from San Antonio to Houston:

1st. half time: 54km/h

2nd. half time: 118 km/h

Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h}  }{2}=86 \frac{km}{h} [\tex]

Driving way back:

1st. half time: 54km/h

2nd. half time: 118 km/h

Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h}  }{2}=86 \frac{km}{h} [\tex]

As in both routes we have the same average speed, then the average speed for the whole trip is 86 km/h

7 0
3 years ago
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imagine a horse pulling a cart. What would happen to the speed of the cart if several bags of cement were adding to the cart?
iogann1982 [59]
Assuming the power delivered by the horse does not change, the speed of the cart will decrease.
In fact, the power delivered by the horse is the work done by the horse (W) per unit time (t):
P=\frac{W}{t}
<span>If several bags are added to the cart, the horse must do more work to transport them. Therefore, W in the fraction increases. But if the power P of the horse is constant, then it means that the time t must increase as well. So, the horse will take more time to transport the car, and this means that the speed of the cart has decreased.</span>
7 0
2 years ago
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Do sound waves always travel in straight lines explain
babunello [35]
They travel like waves. Just throw rock at lake you will see wave. When it bumps to barrier barrier reflects some part of it . Not like a line lika a wave
3 0
2 years ago
A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combin
Greeley [361]

Answer:

<em>The equivalent resistance of the combination is R/100</em>

Explanation:

<u>Electric Resistance</u>

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}

If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}...+\frac{1}{R/10}

This sum is repeated 10 times. Operating each term:

\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}

All the terms have the same denominator, thus:

\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}

Taking the reciprocals:

R_e=R/100

The equivalent resistance of the combination is R/100

6 0
3 years ago
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