Answer:
Power = 371.28 kW
Explanation:
Initial pressure, P1 = 5 bar
Final pressure, P2 = 1 bar
Initial temperature, T1 = 320°C
Final temperature, T2 = 160°C
Volume flow rate, V = 0.65m³/s
From steam tables at state 1,
h1 = 3105.6 kJ/kg, s1 = 7.5308 kJ/kgK
v1 = 0.5416 m³/kg
Mass flow rate, m = V/v1
m = 1.2 kg/s
From steam tables, at state 2
h2 = 2796.2 kJ/kg, s2 = 7.6597 kJ/kgK
Power developed, P = m(h1 - h2)
P = 1.2(3105.6-2796.2)
P = 371.28 kW
Answer:
The youth hockey training facility
Explanation:
Answer:
(a) E = 0 N/C
(b) E = 0 N/C
(c) E = 7.78 x10^5 N/C
Explanation:
We are given a hollow sphere with following parameters:
Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C
R = radius of sphere = 26.1 cm = 0.261 m
Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²
The formula for the electric field intensity is:
E = (1/4πεo)(Q/r²)
where, r = the distance from center of sphere where the intensity is to be found.
(a)
At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.
<u>E = 0 N/C</u>
(b)
Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).
<u>E = 0 N/C</u>
(c)
Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:
E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]
<u>E = 7.78 x10^5 N/C</u>
I think the answer is B. 10D
