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Mazyrski [523]
3 years ago
15

You are given that kc = 10-1 kg eq-1 min-1, ku = 10-3 kg2 eq-2 min-1 and [A]0 = 10 eq kg-1, where kc is the rate constant for a

catalyzed step-growth polymerization, ku is the rate constant for an uncatalyzed step-growth polymerization, and [A]0 is the initial concentration of monomer A in the step-growth polymerization. Assume that the stoichiometry of monomer A to monomer B is 1:1, that the reactive groups on A only react with the reactive groups on B, and that the reactivity of A and B is independent of the chain length.
A. Calculate the time in minutes for conversion (p) to reach values of 0.2, 0.4, 0.6, 0.8, and 0.99 for both catalyzed and uncatalyzed polymerizations.B. Next, calculate the number-average degree of polymerization at each of these times.C. Assume that you can recover all of the catalyst (i.e., the cost of the catalyst is not a factor), which polymerization route is more economical from an industrial perspective?
Engineering
1 answer:
victus00 [196]3 years ago
7 0

Answer:

-ajkdbvójadh`toug511

Explanation:

b

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Answer:

When you pull the trigger to shoot a shotshell from a shotgun or a cartridge from a rifle or handgun, the firing pin strikes the primer in the base of the cartridge or shotshell. This causes the primer to explode. The spark from the primer ignites the gunpowder, which burns rapidly and converts to a gas.

Explanation:

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A continuous random variable, X, whose probability density function is given by f(x) = ( λe−λx , if x ≥ 0 0, otherwise is said t
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Answer:

a) F(x) = \lambda \int_0^{\infty} e^{-\lambda x} dx= -e^{-\lambda x} \Big|_0^{\infty} = 1- e^{-\lambda x} \

b) P(10 < X

Explanation:

Previous concepts

The cumulative distribution function (CDF) F(x),"describes the probability that a random variableX with a given probability distribution will be found at a value less than or equal to x".

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution".

Part a

Let X the random variable of interest. We know on this case that X\sim Exp(\lambda)

And we know the probability denisty function for x given by:

f(x) = \lambda e^{-\lambda x} , x\geq 0

In order to find the cdf we need to do the following integral:

F(x) = \lambda \int_0^{\infty} e^{-\lambda x} dx= -e^{-\lambda x} \Big|_0^{\infty} = 1- e^{-\lambda x} \

Part b

Assuming that X \sim Exp(\lambda =0.1), then the density function is given by:

f(x) = 0.1 e^{-0.1 x} dx , x\geq 0

And for this case we want this probability:

P(10 < X

And evaluating the integral we got:

P(10 < X

4 0
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Neither of the technicians are correct.

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Given a books table with columns named book_title and year_released, the following SQL statement will select the number of books
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Question Continuation

True or False?

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