Answer: making sure that they are up to date
Explanation:
Known :
Q = 300 L/s = 0.3 m³/s
D1 = 350 mm = 0.35 m
D2 = 700 mm = 0.7 m
g = 9.81 m/s²
Solution :
A1 = πD1² / 4 = π(0.35²) / 4 = 0.096 m²
A2 = πD2² / 4 = π(0.7²) / 4 = 0.385 m²
hL = (kL / 2g) • (U1² - U2²)
hL = (kL / 2g) • Q² (1/A1² - 1/A2²)
hL = (1 / 2(9.81)) • (0.3²) • (1/(0.096²) - 1/(0.385²))
hL = 0.467 m
Answer:
Given that
LHS of above given equation have dimension ![[M^oL^{1}T^{-1}]](https://tex.z-dn.net/?f=%5BM%5EoL%5E%7B1%7DT%5E%7B-1%7D%5D)
.
Now find the dimension of RHS
Dimension of P = ![[ML^{-1}T^{-2}]](https://tex.z-dn.net/?f=%5BML%5E%7B-1%7DT%5E%7B-2%7D%5D)
.
Dimension of d= ![[M^{0}L^{1}T^{0}]](https://tex.z-dn.net/?f=%5BM%5E%7B0%7DL%5E%7B1%7DT%5E%7B0%7D%5D)
.
Dimension of μ = ![[ML^{-1}T^{-1}]](https://tex.z-dn.net/?f=%5BML%5E%7B-1%7DT%5E%7B-1%7D%5D)
.
Dimension of L= .
So
![\dfrac{\Delta Pd^2}{32\mu L}=\dfrac{[ML^{-1}T^{-2}].[M^{0}L^{1}T^{0}]^2}{[ML^{-1}T^{-1}].[M^{0}L^{1}T^{0}]}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20Pd%5E2%7D%7B32%5Cmu%20L%7D%3D%5Cdfrac%7B%5BML%5E%7B-1%7DT%5E%7B-2%7D%5D.%5BM%5E%7B0%7DL%5E%7B1%7DT%5E%7B0%7D%5D%5E2%7D%7B%5BML%5E%7B-1%7DT%5E%7B-1%7D%5D.%5BM%5E%7B0%7DL%5E%7B1%7DT%5E%7B0%7D%5D%7D)
![\dfrac{\Delta Pd^2}{32\mu L}=[M^0L^{1}T^{-1}]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20Pd%5E2%7D%7B32%5Cmu%20L%7D%3D%5BM%5E0L%5E%7B1%7DT%5E%7B-1%7D%5D)
It means that both sides have same dimensions.
Answer:
the ability to absorb or avoid damage without suffering complete failure and is an objective of design, maintenance and restoration for buildings and infrastructure
Explanation:
The equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.
<h3>
What is resistance?</h3>
Resistance is the obstruction offered whenever the current is flowing through the circuit.
So the equivalent resistance is when three resistances are connected in series. When the resistances are connected in series then the voltage is different and the current remain same in each resistance.
V eq = V₁ + V₂ + V₃
IReq = IR₁ + IR₂ + IR₃
Req = R₁ + R₂ + R₃
Therefore the equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.
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