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Free_Kalibri [48]
4 years ago
15

PLEASE HELP FASTTTT THANKS

Mathematics
1 answer:
bearhunter [10]4 years ago
5 0

The answer is [ 1/2; reduction ]

The length of the large square is 4 units.

The length of the small square is 2 units.

Divide to find the scale factor:

2 / 4 = 2/4 = 1/2

Since the larger square turns into a smaller square, it is a reduction.

This proves that Option B is correct.

Best of Luck!

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There are (10^8 )2 × 10
Natali5045456 [20]

Answer:

2,000,000,000

Step-by-step explanation:

100,000,000 x 2 = 200,000,000

200,000,000 x 10 =2,000,000,000‬

7 0
3 years ago
What is the image of (3, 3) after a dilation by a scale factor of 5 centered at<br> the origin?
Savatey [412]

778574 y p py gtoivu goy giov ou ouvyh yuovb ouyhv uo

6 0
3 years ago
10 points. [ATTACHED]
SVETLANKA909090 [29]

Answer:

\overline{AD}\:=\:19.2

Step-by-step explanation:

2x+5=3x-2\quad \:\rightarrow \quad \:x=7\\\\\overline{BD}\:=\:3\left(7\right)-2\:=\:19\\\\Length\:of\:\overline{AD}\:=\sqrt{19^2+2.5^2}=19.2

3 0
4 years ago
Suppose that from a group of 9 men, 1 will be randomly chosen for a dangerous assignment, and suppose that the chosen man will b
tangare [24]

Answer:

1/54

Step-by-step explanation:

1/9 x 1/6

8 0
3 years ago
The sum of three numbers is 54. the third number is 2 times the first. the first number is 6 more than the second. what are the
vaieri [72.5K]
Hello!

To solve this, we will use a system of equations. We will have the numbers be represented by x, y, and z, where x will represent the first, y the second, and z the third.

x+y+z=54
z=2x
x=6+y

We know that x is equal to 6+y. We can plug this into the second equation to find z.

z=12+2y

Now we can plug these y values into the first equation to find y.

6+y+y+12+2y=54
18+4y=54
4y=36
y=9

Now we know the value of y. We can plug this into the equations to find the other values.

x=6+9
x=15

z=15(2)
z=30

Just to check, we will add them all up and see if they equal 64.

15+9+30=54

The first number is 15, the second is 9, and the third is 30.

I hope this helps!

4 0
3 years ago
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