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ivann1987 [24]
3 years ago
15

_____________(kinetic energy released in matter) specifies the intensity of x-rays at a given point in air at a known distance f

rom the focal spot or source of x-rays, and the cumulative or total ___________(same word) will be monitored during the fluoroscopic procedure
Physics
1 answer:
Natali [406]3 years ago
8 0

Answer:

Air kerma

Explanation:

The acronym for the word 'kerma' is $\text{"kinetic energy released per unit mass"}$. It is the sum or the total of the kinetic energies of the $\text{charged particles}$ that is liberated by the uncharged ionizing radiation in the small sample of a matter, and is divided by the mass of that sample.

It is sometimes used for expressing the radiation concentration that is delivered to a point.

It is used to specify the intensity of the x-rays for any given point in the air at some known distance form the local spot. The total air kerma can be monitored in the fluoroscopic procedure.

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What is the acceleration of a car that maintains a constant velocity of 100km/h for 10 s
Mademuasel [1]
A constant velocity means the acceleration is zero.
4 0
3 years ago
Read 2 more answers
A thin film of MgF₂ (n = 1.38) coats a piece of glass. Constructive interference is observed for the reflection of light with wa
TEA [102]

Answer:

t = 905.8 nm

Explanation:

Given:

- Wavelength λ_1 = 500 nm

- Wavelength λ_2 = 625 nm

- MgF₂ refractive index n = 1.38

Find:

What is the thinnest film for which this can occur?

Solution:

- We have two different wavelength of light that constructively interfere at the surface of the film. We need the minimum thickness of film that would satisfy the condition of constructive interference for both!

-Since the refractive index of glass is greater than that of MgF_2, the expression of constructive interference would be as follows:

                                2*t = m*λ / n

- Since, the orders m are unknown for each wavelength, also different. We will try to determine the first for each wavelength of light.

- Construct two equation:

                                t = m_1*(500 nm ) / (2*1.38 )

                                t = 181.1594203*m_1  nm

                                t = m_2*(625 nm ) / (2*1.38 )

                                t = 226.4492754*m_2  nm

- Now equate the two thicknesses which should be equal:

                               226.4492754*m_2 = 181.1594203*m_1

                               m_2 = 0.8*m_1

- Now we know that m can only take integer values, and m is proportional to thickness t. So for thinnest thickness m's must take the least integer values. Hence, we have:                    

                               m_2 = (4 / 5) * m_1

So,                           m_1 = 5 , m_2 = 4   ..... Least integer values.

- Now that we have m's we can compute the thickness t as follows:

                                t = 181.1594203*m_1  nm

- Substitute m_1 = 5, we have:

                                t = 181.1594203*5  nm

                               t = 905.8 nm

- Substitute m_2 = 4 in:

                                 t = 226.4492754*m_2

                                 t = 226.4492754*4

                                t = 905.8 nm

- Our values of t = 905.8 nm matches for both wavelengths.

                                   

7 0
4 years ago
1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wa
love history [14]

Answer:

ans \:  = \boxed{{4.8 \times 10}^{ - 4}  Hz}

Explanation:

given \to \\  f_{r} = 350 \:  \\ v_{r} =  {3 \times 10}^{8}  \\ but \to \\ v = f \gamma   \to \:  \gamma  =  \frac{v}{f}  : hence \to \\  \gamma _{r} =  \frac{v_{r}}{f_{r}}   =  \frac{3 \times 10^{8} }{350}   =  \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\  f_{w} = water \: frequency = \:  \boxed{  ?}\:  \\ v_{w} =  14 50 \\ but \to \\ v = f \gamma   \to \:  \gamma  =  \frac{v}{f}  : hence \to \\  \gamma _{w} =  \frac{v_{w}}{f_{w}}   =  \frac{1}{100}  \times \gamma _{r}  =  \frac{1}{100}  \times 857,142.85714  \\\gamma _{w}  =  \boxed{8,571.4285714 \: m} : hence \to \:  \\ f_{w} =  \frac{v_{w}}{ \gamma _{w}}  =  \frac{1450}{8,571.4285714}  =  \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) =  \frac{f_{w}}{f_{r}}  =  \frac{0.1691666667}{350}  = 0.0004833333 \\ hence \to \\ the  \: frequency  \: of \:  the \:  radio  \: wave  \: is \to \:   \boxed{{4.8 \times 10}^{ - 4}  }\:  \\ that  \: of  \: the \:  wave  \: created  \: in  \: the  \: water.

♨Rage♨

8 0
3 years ago
Pressure = weight density × depth
Irina-Kira [14]

As we know that pressure due to water is given as

Pressure = (weight density) (Depth)

here we know that

weight density of water = 9800 N/m^3

height of the water = 1.2 m

now from above formula we have

P = 9800 \times 1.2

P = 11760 Pa

so pressure due to water is given as 11760 Pascal

6 0
3 years ago
1. Which types of planets are more dense: terrestrial or
lubasha [3.4K]

Answer:

1. terrestrial

2. The distance light travels in one year

Explanation:

7 0
3 years ago
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