The ratio of the forces is 9.59×10^-4.
The transverse speed in terms of tension in the string (T) of the wave is,
ω/k=√T/μ
T=ω^2k$2μ
Substituting the values we get,
T=[(50.0rad/s)^2/(0.800m−1)^2]×(12.0×10−3kg/m)
≈46.9N
The ratio of the transverse force and the tension is,
F/T=0.045N/46.9N
≈9.59×10^-4
Hence, the ratio of the forces is 9.59×10^-4.
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The momentum of an object is the product between the mass m of the object and its velocity:
The truck in our problem has momentum equal to
and a mass of
so, if we re-arrange the previous formula, we can use these data to find the velocity of the truck:
Any object that's moving has <em>kinetic</em> energy.
Its kinetic energy is (1/2)·(its mass)·(its speed squared) Joules.
Answer:
v= 17.15 m/s
Explanation:
mass of the book=0.1 Kg
height above ground, h= 15 m
Using conservation of energy
Potential energy is converted into kinetic energy
v= 17.15 m/s
Hence, the book will hit the ground at the speed of 17.15 m/s.