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liberstina [14]
3 years ago
14

A device that does work with one movement and changes the size or direction of a force is a(n)

Physics
2 answers:
tresset_1 [31]3 years ago
7 0
A device that does work with one movement and changes the size or direction of a force is a simple machine.
inessss [21]3 years ago
7 0

Answer:

it is a simple machine

Explanation:

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Answer: A.Validate and implement the results.

The final step in a forecasting system is to validate and implement the results. This can be similar to a presentation. After going through all the steps from the planning, researching, and gathering of data, making the forecast, validating and implementing the results will be the last thing that needs to be done.

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Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou
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Answer:

a. The station is rotating at 1.496 \frac{rev}{min}

b. the rotation needed is 2.8502 \frac{rev}{min}

Explanation:

We know that the centripetal acceleration is

a_{c}= \omega ^2 r

where \omega is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).

<h3>a. </h3>

The rotational speed  is :

2.7 \frac{m}{s^2} = \omega ^2 * 110  \ m

\omega ^2 = \frac{2.7 \frac{m}{s^2}} {110 \ m}

\omega  = \sqrt{ 0.02454 \frac{rad^2}{s^2} }

\omega  = 0.1567 \frac{rad}{s}

Knowing that there are 2\pi \ rad in a revolution and 60 seconds in a minute.

\omega  = 0.1567 \frac{rad}{s}  \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}

\omega  = 1.496 \frac{rev}{min}

<h3>b. </h3>

The rotational speed needed is :

9.8 \frac{m}{s^2} = \omega ^2 * 110  \ m

\omega ^2 = \frac{9.8 \frac{m}{s^2}} {110 \ m}

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\omega  = 0.2985 \frac{rad}{s}

Knowing that there are 2\pi \ rad in a revolution and 60 seconds in a minute.

\omega  = 0.2985 \frac{rev}{min}  \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}

\omega  = 2.8502 \frac{rev}{min}

3 0
3 years ago
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A student wants to determine the impulse delivered to the lab cart when it runs into the wall. The student measures the mass of
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Impulse = Force * times and also Impulse = change in momentum.

Given that the mass does not change, change if momentum = mass * (final velocity -  initial velocity)

Given that you know mass and initial velocity (which is the velicity before the cart hits the wall) you need the final velocity (which is the velocity after the cart hits the wall).

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How speed and position affect the energy possess by an object?​
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Answer:

D. Tidal energy is replaced naturally by the Moon's gravity.

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