Question

HELP what's the distance for this question? ​

Answer 1

Answer:

$Distance = 38.57ft$

Step-by-step explanation:

Given

$Base = 60$

$\theta = 50$

Required

The distance between the top and John

The distance is calculated using:

$sin\alpha = \frac{Distance}{Base}$

Where

$\alpha = 90 - \theta$ --- the angle between the diagonal line and the vertical line

$\alpha = 90 - 50$

$\alpha = 40$

So, we have:

$Sin(40) = \frac{Distance}{60}$

$Distance = 60 * sin(40)$

$Distance = 60 * 0.6428$

$Distance = 38.57ft$

$Distance = 986 * tan(38)$

$Distance = 986 * 0.7812$

$Distance = 770ft$ --- approximated