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Neporo4naja [7]
3 years ago
6

Which of the following ratios is equivalent to 2:3 A) 1/2 B) 4/6 C) 12/13 D)20/25

Mathematics
2 answers:
lord [1]3 years ago
8 0

Answer:

B)4/6

Step-by-step explanation:

kicyunya [14]3 years ago
4 0

Answer:

B:4/6

Step-by-step explanation:

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-14n - 2r - 21

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What is the value of x in the equation (3/4 + 5/8) x = 3/5
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10.04 × 8.8= ?<br><br>can you help me again please​
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Name a pair of alternate interior angles in the diagram. <br> -a.<br> -b.<br> -c.<br> -d.
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For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0
2 years ago
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