T = tens, h = hundreds
t + h = 26...t = 26 - h
10t + 100h = 1610
10(26 - h) + 100h = 1610
260 - 10h + 100h = 1610
-10h + 100h = 1610 - 260
90h = 1350
h = 1350/90
h = 15
t + h = 26
t + 15 = 26
t = 26 - 15
t = 11
so there is 11 tens and 15 hundreds
We are given function: ![M(x) = 6x^2-12.](https://tex.z-dn.net/?f=M%28x%29%20%3D%206x%5E2-12.)
Let us find it's inverse.
In order to find it's inverse, we need to get function equal to y.
![y= 6x^2-12](https://tex.z-dn.net/?f=y%3D%206x%5E2-12)
Switching x and y's .
![x= 6y^2-12](https://tex.z-dn.net/?f=x%3D%206y%5E2-12)
Now, solving it for y.
![x+12 = 6y^2](https://tex.z-dn.net/?f=x%2B12%20%3D%206y%5E2)
Dividing both sides by 6, we get
![y^2=\frac{x}{6} +\frac{12}{6}](https://tex.z-dn.net/?f=y%5E2%3D%5Cfrac%7Bx%7D%7B6%7D%20%2B%5Cfrac%7B12%7D%7B6%7D)
![y^2=\frac{x}{6} +2](https://tex.z-dn.net/?f=y%5E2%3D%5Cfrac%7Bx%7D%7B6%7D%20%2B2)
Taking square root on both sides, we get
![\sqrt{y^2} =\sqrt{\frac{x}{6} +2}](https://tex.z-dn.net/?f=%5Csqrt%7By%5E2%7D%20%3D%5Csqrt%7B%5Cfrac%7Bx%7D%7B6%7D%20%2B2%7D)
![y=\sqrt{\frac{x}{6} +2}](https://tex.z-dn.net/?f=y%3D%5Csqrt%7B%5Cfrac%7Bx%7D%7B6%7D%20%2B2%7D)
Re-writing in the form of given inverse.
![m^{-1}(x)=\sqrt{\frac{x}{3\times2} +2}](https://tex.z-dn.net/?f=m%5E%7B-1%7D%28x%29%3D%5Csqrt%7B%5Cfrac%7Bx%7D%7B3%5Ctimes2%7D%20%2B2%7D)
On comparing with given M^-1 = √((x/3k)+k).
![\sqrt{\frac{x}{3k} +k} = \sqrt{\frac{x}{3\times2} +2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bx%7D%7B3k%7D%20%20%2Bk%7D%20%3D%20%5Csqrt%7B%5Cfrac%7Bx%7D%7B3%5Ctimes2%7D%20%2B2%7D)
k=2.
<h3>Therefore, correct option is C.) k = 2.</h3>
It’s 8.9 because in a simpler way 8 is greater than 7
Divide 138.16 by 3.14. This gives a diameter of 44 meters.
Hope this helped :)
It is said in the question that set A have elements which are even whole number between 0 and 2.
Whole number means no decimal number. And there is no even whole numbers between 0 and 2.
So set A contains no such elements. Hence we can say that , it is null .