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2 years ago

Which of the following ratios is equivalent to 2:3 A) 1/2 B) 4/6 C) 12/13 D)20/25

Mathematics

2 answers:

lord [1]2 years ago

8 0

Answer:

B)4/6

Step-by-step explanation:

kicyunya [14]2 years ago

4 0

Answer:

B:4/6

Step-by-step explanation:

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4 - 3d = d - 8 solve for d

torisob [31]

Well you subtract d from both sides with would make 2D-4=-8. Then you subtract four to both sides which is -12. Then you divide -12 by 2D which is 6. D=-6

8 0

3 years ago

Please Help Keep getting 6.4

elixir [45]

Answer:

r = 3

Step-by-step explanation:

x^2 + 6x + y^2 - 8y = - 16

Take half the linear term and square it.

x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16

Add the squared amounts to the right.

x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16

Combine on the right.

x^2 + 6x + 9 + y^2 - 8y + 16 = 9

Represent the 2 quadratics as perfect squares.

(x + 3)^2 + y - 4)^2 = 9

The radius is the square root of 9 which is 3

8 0

2 years ago

Read 2 more answers

A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w

sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

7 0

2 years ago

6m^2 + 7n Identify the constant, variable, and terms

Leokris [45]

<h3>Answer:</h3>

Given equation :- 6m² + 7n

where,

Constant = 0.
Variable = m, n.
Terms = 6m² , 7n.

6 0

2 years ago

The advertised duration of the trip is 2 hours and 15 minutes. The company operating the ferry would like to increase its operat

vesna_86 [32]

The 2.88 minutes have to reduce the standard deviation to increase the efficiency.

According to the statement

we have given that the duration of the trip is 2 hours and 15 minutes. And we have to how much standard deviation be reduced to increase the operational efficiency.

So, For this purpose, we know that the

Let X be the time taken to reach the resort. Then it is given that the

N (μ , σ).

Here μ is 2 hours then

μ = 2*60 = 120 minutes.

And

Let σ be the reduced standard deviation such that new distributions becomes N (μ , σ)

Then P ( x <135)

here 135 is the minute format of 2 hours and 15 min.

So,

P ( x <135) = 0.95

And

P [ (x -120 / σ) < (135 -120 / σ)] = 0.95

P [ Z < ( 15 / σ)] = 0.95

And after solving it the

σ = 9.22 min.

i.e. 12 - 9.22 = 2.88 min.

So, The 2.88 minutes have to reduce the standard deviation to increase the efficiency.

Learn more about Standard deviation here

brainly.com/question/475676

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The time it takes for a ferry to reach a summer resort from the mainland is Normally distributed with mean 2 hours and standard deviation 12 minutes. The advertised duration of the trip is 2 hours and 15 minutes. The company operating the ferry would like to increase its operational efficiency by reducing the standard deviation so that they are on time 95% of the time. How much do they have to reduce the standard deviation

#SPJ4

5 0

1 year ago