Original price $77.00<br> markdown: 32%<br> sale price

Stars that are medium-sized are: A. about the size of our sun B. about four times the size of our sun C. less than half the size

aliina [53]

C because the sun is like 100 times bigger than our Earth so if its medium well there we go

8 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

3 years ago

One fifth of the sum of two angles is 24 and half their difference is 14.Calculate the two angles

Brums [2.3K]

Let, the angles = a, b
It is given that, a+b /5 = 24
a + b = 120 --- equation (1)

a-b/2 = 14
a - b = 28 ---- equation (2)
a = 28 + b

Now, substitute this value of b in equation (1),
28 + b + b = 120
2b = 120 - 28
b = 92/2
b = 46
Now, a = 28 + b = 28 + 46 = 74

In short, Your Angles are 74 and 46

Hope this helps!

4 0

3 years ago

The circle shown below has a diameter of 18 centimeters. What is the area of the shaded sector?

N76 [4]

Area of circle = Pi x r*2

If diameter is 18, radius is 9.

Area = pi (3.14) x r*2 (9*2 = 81) .. 3.14 x 81 = 254.34 sq cen = total area of circle.

A circle is 360 degrees, the shaded area is 270 degrees. the shaded area is 3/4 (270/360) of the area of the circle.

254.34 x 3/4 = 190.755 sq cen

Hope this helps

7 0

3 years ago

Read 2 more answers

Rob is saving to buy a new MP3 player. For every $15 he earns babysitting, he saves $9. On Saturday, Rob earned $60 babysitting.

alexandr402 [8]

$60 ÷ $15 = 4
$9 × 4 = $36
he saved $36 when he earned $60

8 0

3 years ago

Original price $77.00 markdown: 32% sale price