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Papessa [141]
2 years ago
9

Find the missing side of The Triangle ​

Mathematics
1 answer:
saul85 [17]2 years ago
7 0

Step-by-step explanation:

By phythagorous theorem,

AC²=AB²+BC²

AC²=36+64

AC²=100

AC=root of 100

AC=10

You might be interested in
Hayden earns $9.50 per hour as a lifeguard.He earns a bonus of $50.00 for taking a training course.How many hours must he work t
mel-nik [20]

Answer: he must work for at least 26.32 hours

Step-by-step explanation:

Let x represent the number of hours that Hayden works as a life guard.

Hayden earns $9.50 per hour as a lifeguard. This means that the amount that he earns for working for x hours would be

9.5x

He earns a bonus of $50.00 for taking a training course. If he takes this bonus cost, the amount that he would earn for working for x hours is

9.5x + 50

Therefore, the number of hours that he must work to earn at least $300.00 would be

9.5x + 50 ≥ 300

9.5x ≥ 300 - 50

9.5x ≥ 250

x ≥ 250/9.5

x ≥ 26.32

4 0
3 years ago
Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
Rhe sum of three consecutive ofd numbers is 87. What is the smallest of these numbers?
neonofarm [45]

Answer:

The smallest of the said odd numbers is 27

Step-by-step explanation:

Since it is 3 odd numbers that sums up to 87, the first thing to do is to divide 87 by 3

That is 87/3 = 29, which is an odd number

The nearest odd  numbers to 29 are 27 and 31, and the total of all these three odd numbers is 87

That is 27+29+31 = 87, which are consecutive odd numbers.

The smallest odd number here is therefore 27

3 0
2 years ago
Explain the rule in solving inequalities with a negative coefficient.
dimulka [17.4K]

Answer:

  the comparison must be reversed when multiplying by a negative

Step-by-step explanation:

The rules of equality apply to solving inequalities, with the exception that multiplication or division by a negative number reverses the sense of the comparison:

  -x > 1

  x < -1 . . . . . multiply both sides by -1

____

Effectively, multiplication (or division) by a negative number is equivalent to reflection across the origin. Things that were ordered left/right (on the number line) are ordered right/left after such a reflection:

  -2 < -1

  1 < 2

_____

<em>Additional comment</em>

Application of any function requires that you pay attention to ordering. Some functions naturally reverse the order; others do so only on specific domains.

Consider f(x) = 1/x.

  1 < 2

  f(1) > f(2) . . . . because the slope of the f(x) function is negative everywhere.

__

<em>In the first and second quadrants</em>, the cosine function also reverses order.

  20° > 10°

  cos(20°) < cos(10°)

__

Probably the most commonly encountered function used with inequalities is the absolute value function.

  |x-3| > 2

This function has one domain where the slope is negative, and another domain where the slope is positive.

  For x < 3, the function negates its argument, so we have ...

     -(x -3) > 2

     -x +3 > 2

     -x > -1

     x < 1 . . . . . everywhere consistent with x < 3

  For x ≥ 3, the function does nothing, so we have ...

     x -3 > 2

     x > 5

  The solution to this absolute value inequality is (x < 1) ∪ (x > 5).

__

You can also resolve negative coefficients by adding the opposite. Addition and subtraction never require any change to the comparison operator.

  -x > 1

  0 > x +1 . . . . x is added

  -1 > x . . . . . . -1 is added

7 0
3 years ago
A church group ordered a total of 22
blagie [28]

Answer:

the group bought 10 burger and 12 drinks

Step-by-step explanation:

6.25×10=62.5

92.50-62.5=30

30÷2.50=12

3 0
2 years ago
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