Answer:
3 moles
Explanation:
3 moles atoms are needed to react with 50 grams of O2 gas.
Answer:
14 H i think , but i believe that thats the answer
Answer:
12 L of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
CS₂ + 3O₂ —> CO₂ + 2SO₂
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Finally, we shall determine the volume of O₂ required to produce 4 L of CO₂. This can be obtained as follow:
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Therefore, xL of O₂ will react to produce 4 L of CO₂ i.e
xL of O₂ = 3 × 4
xL of O₂ = 12 L
Thus, 12 L of O₂ is needed for the reaction.
One box is 120g.
mass of 126 boxes = 126*120 = 15120 g
(note: used an additional significant figure when first digit is a 1, so four significant figures)
Using the conversion 1 lb. = 453.6 g/lb
15120g = 15120 g / (453.6 g/lb) = 15120 g * (1/453.6) lb/g = 33.3 lbs. (3 significant figures)
