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timama [110]
3 years ago
7

Copper, a metal known since ancient times, exists in two stable isotopic forms, 6329Cu (69.09%) and 6529Cu (30.91%). Their atomi

c masses are 62.93 amu and 64.9278 amu respectively. Calculate the average atomic mass of copper.
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
7 0

Answer:

Wt. Avg. Atomic Weight => 63.35457 amu

Explanation:

Given              Isotopic             %Abundance     fractional          Wt Avg

                  At. Mass (amu)                                  abundance      contribution                    

Cu-63              62.93                      69.09              0.6909            43.4783

Cu-65              64.9278                  20.0668        0.200668        20.0668

Wt Average of all isotopes = ∑Wt Avg Contributions

=  43.4783 amu + 20.0668 amu = 63.35457 amu

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3 years ago
Which reactions are single displacement reactions? 2NaBr + CaF2 → 2NaF + CaBr2 SnO2 + 2H2 → Sn + 2H2O 4Na + O2 → 2Na2O 2KClO3 →
r-ruslan [8.4K]

Answer : The correct options are, SnO_2+2H_2\rightarrow Sn+2H_2O and 2Al+6HCl\rightarrow 2AlCl_3+3H_2

Explanation :

Single displacement reaction : It is a type of chemical reaction in which the more reactive element displaces the less reactive element.

Option A reaction : 2NaBr+CaF_2\rightarrow 2NaF+CaBr_2

It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.

Option B reaction : SnO_2+2H_2\rightarrow Sn+2H_2O

It is an example of single displacement reaction.

Option C reaction : 4Na+O_2\rightarrow 2Na_2O

It is an example of combination reaction because in this reaction two reactants react to give a single product.

Option D reaction : 2KClO_3\rightarrow 2KCl+3O_2

It is an example of decomposition reaction because in this reaction a single reactant decomposes into two or more products.

Option E reaction : 2Al+6HCl\rightarrow 2AlCl_3+3H_2

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5 0
3 years ago
Calculate the mole mass of following compound<br> FeSO4
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3 0
2 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂  +  I₂   ⇄   2HI

Initially we have 0.001 molesof H₂

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If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

           H₂     +      I₂      ⇄   2HI

In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is =  (HI)² / (H₂) . (I₂)

0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

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slamgirl [31]

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8 0
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