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vladimir1956 [14]
2 years ago
5

Unicorn I need your help

Mathematics
1 answer:
GarryVolchara [31]2 years ago
7 0

Answer:

plz Send the complete picture as optional are not visible ...

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How do I solve this question I’ve been stuck on this since last night
meriva

Observation one

From the markings on the diagram <1 = 60o The left triangle is at least isosceles. Therefore equal sides produce equal angles opposite them.

Now we have accounted for 2 angles that are equal (each is 60 degrees) and add up to 120 degrees. The third angle (angle 2) is found from this equation.

<1 + 60 + <2 = 180 degrees.  All triangles have 180 degrees.

60 + 60 + <2 = 180

Observation 2

<2 = 60 degrees.

120 + <2 = 180

m<2 = 180 - 120

m<2 = 60 degrees.

Observation 3

m<3 = 120

<2 and <3 are supplementary.

Any 2 angles on the same straight line are supplementary

60 + <3 = 180

<3 = 180 - 60

<3 = 120

Observation 4

m<4 = 40 degrees.

All triangles have 180 degrees. No exceptions.

m<4 + 20 +m<3 = 180

m<4 + 20 + 120 = 180

m<4 + 140 = 180          

m<4 = 180 - 140

m<4 = 40


8 0
3 years ago
Randy has 128 ounces if dog food he feeds his dog. 8 ounces of food each day how many days will the dog food last
OverLord2011 [107]
All you have to do is divide the ounces he has into how much he gives the dog each day so 128/8 is 16
3 0
3 years ago
Read 2 more answers
Find the domain and the range of the following function
adell [148]

Answer:

cjvnvhhvhjgufvjffuhghhhvc

6 0
2 years ago
A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
3 years ago
I need answer asap pls help
MariettaO [177]

Answer: A= (3,-3) . B(4,1). C= (1,0)

Step-by-step explanation:

7 0
3 years ago
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