Which equations represents the relationship shown in the graph?

Mathematics

1 answer:

eduard2 years ago

4 0

Answer:

I am pretty sure it is y=-3x

Let me know if it was right!

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factor completely 4x5 − 20x4 − 36x3. 4(x5 − 5x4 − 9x3) x3(4x2 − 20x − 36) x2 − 5x − 9 4x3(x2 − 5x − 9)

Mila [183]

Consider the polynomial $4x^5 - 20x^4 - 36x^3.$ It has three terms and their greatest common factor is $4x^3.$

Since

$4x^5=4x^3\cdot x^2,\\20x^4=4x^3\cdot 5x,\\36x^3=4x^3\cdot 9,$

then

$4x^5 - 20x^4 - 36x^3=4x^3(x^2-5x-9)$ (you write in brackets the same sign as the corresponding term has).

Answer: correct choice is D.

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Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.

adoni [48]

again, let's assume daily compounding means 365 days per year.

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}$

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}$

$A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}$