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Ksenya-84 [330]
2 years ago
11

Which equations represents the relationship shown in the graph?

Mathematics
1 answer:
eduard2 years ago
4 0

Answer:

I am pretty sure it is y=-3x

Let me know if it was right!

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3.4 hours

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Values equivalent to 1/4​
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0.25, 4/16, theres like a million more

Step-by-step explanation:

is that what youre looking for?

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Find the value of 81 3x
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A punch recipe that serves 24 people calls for 4 liters of lemon-lime soda, 2 pints of sherbet, and 6 cups of ice. How much of e
Tatiana [17]
Find out how much you need for one person then multiply by 18 is one way you could do this..

4 divided by 24 = 0.166666666666667 x 18 = 3 litres of lemon-lime soda.

2 divided by 24 = 0.083333333333333 x 18 = 1.5 pints of servet

6 divided by 24 = 0.25 x 18 = 4.5 cups of ice.

Hope this helps!
Your teacher may have wanted you to (some how) use your 6x tables to work this out?!

8 0
3 years ago
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A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

8 0
3 years ago
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