Answer:
t = (A/sx) - r
Step-by-step explanation:
Solve for t like this:

If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Answer:
2y = x + 2
Step-by-step explanation:
Looking at the graph, we can see from one point to the next (from right to left), the x-value rises by 2 and the y-value by 1;
From this we can work out the gradient between two points using the formula, i.e. the change/difference in y divided by the change/difference in x:

Joining the points gives a straight line, which means a constant gradient of ¹/₂
Use the line equation formula to get the function:
y - y₁ = m(x - x₁)
m = ¹/₂
x₁ = 0
y₁ = 1
y - 1 = ¹/₂.(x - 0)
y - 1 = ¹/₂.x
2y - 2 = x
2y = x + 2
Answer:
5y+6x-40=0
Step-by-step explanation:
y-2=-6/5(x-5)
5y-10=-6(x-5)
5y-10=-6x+30
5y+6x-10-30=0
5y+6x-40=0