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2 years ago

Consider w1 = 4 + 2i and w2 = –1 – 3i. Which graph represents the sum w1 + w2?

Mathematics

2 answers:

zubka84 [21]2 years ago

7 0

Answer:

Option (2)

Step-by-step explanation:

Two points having real and imaginary parts are,

w₁ = 4 + 2i

w₂ = -1 - 3i

By adding these numbers,

w₁ + w₂ = (4 + 2i) + (-1 - 3i)

= (4 - 1) + (2 - 3)i

= 3 - (1)i

Since, coordinates of a number on the graph are (x, y)

Here x = Real part

y = Imaginary part

Therefore, sum of these numbers will be (3, -1).

Option (2) will be the correct graph.

Serjik [45]2 years ago

5 0

Answer:

graph B

Step-by-step explanation:

EDG21 I did the unit test.

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Paul [167]

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2 years ago

A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer

OLEGan [10]

Answer:

The probability is $P( p < 0.9207) = 0.0012556$

Step-by-step explanation:

From the question we are told

The population proportion is $p = 0.96$

The sample size is $n = 227$

The number of graduate who had job is k = 209

Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

$\mu_x = p = 0.96$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{\frac{p (1 - p )}{n} }$

=> $\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }$

=> $\sigma = 0.0130$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{209}{227}$

=> $\^ p = 0.9207$

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

$P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )$

$\frac{\^ p - p}{\sigma } = Z (The \ standardized \ value\ of \ \^ p )$

$P( p < 0.9207) = P(Z< -3.022 )$

From the z table the area under the normal curve to the left corresponding to -3.022 is

$P(Z< -3.022 ) = 0.0012556$

=> $P( p < 0.9207) = 0.0012556$

6 0

3 years ago

A standard die is rolled 360 times in hopes of rolling a 5 or 6. So the probability of success is p=1/3. Find the standard devia

lana [24]

Answer: option 1 is the correct answer

Step-by-step explanation:

Number of times for which the die was rolled is 360. It means that our sample size, n is 360.

The probability of rolling a 5 or a 6 is 1/3. It means that probability of success,p = 1/3. The probability of failure,q is

1 - probability of success. It becomes

1 - 1/3 = 2/3

The formula for standard deviation is expressed as

√npq. Therefore

Standard deviation = √360 × 1/3 × 2/3

= √80 = 8.9443

Standard deviation is approximately 8.9

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