Answer:
The forward reaction is an exothermic reaction.
Explanation:
An exothermic reaction is one in which energy is released, usually in the form of heat hence the enthalpy of the reaction is negative. When a reaction exothermic, the energy of the reactants is greater than the energy of the products hence the excess energy is given out as heat. The reactants lie at a higher energy level in the reaction profile compared to the products.
When we look at the reaction given in the question, NO(g) ⇌ 12N2(g) + 12O2(g) ΔH = −90.3 kJ , we can easily see from the thermochemical reaction that the forward reaction is exothermic, energy is released by the reaction system as evidenced by the negative enthalpy of reaction.
Answer:
pH = 9.03
Explanation:
The equilibrium of the NH₄Cl / NH₃ buffer in water is:
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Initial moles of both NH₃ and NH₄⁺ are:
0.100L ₓ (0.20 mol / L) = <em>0.0200 moles </em>
The NH₃ reacts with HCl producing NH₄⁺, thus:
NH₃ + HCl → NH₄⁺ + Cl⁻
<em>That means, moles of HCl added to the solution are the same moles are consumed of NH₃ and produced of NH₄⁺</em>
Moles added of HCl were:
0.025L ₓ (0.20mol / L) = 0.0050 moles of HCl. Thus, final moles of NH₃ and NH₄⁺ are:
NH₃: 0.0200 moles - 0.0050 moles = 0.0150 moles
NH₄⁺: 0.0200 moles + 0.0050 moles = 0.0250 moles.
Using H-H equation for bases:
pOH = pKb + log [NH₄⁺] / [NH₃]
<em>Where pKb is -log Kb =</em><em> 4.745</em><em>.</em>
Replacing:
pOH = 4.745 + log 0.0250mol / 0.0150mol
pOH = 4.967
As pH = 14- pOH
<em>pH = 9.03</em>
<em />
Answer:
1569 torr
Explanation:
Assuming ideal behaviour and constant temperature, we can solve this problem by using <em>Boyle's law</em>, which states:
Where in this case:
We <u>input the data given by the problem</u>:
- 202 mL * 505 torr = 65.0 mL * P₂
And <u>solve for P₂</u>:
The original mass of krypton 81 that is present in the ice is 6.70 grams.
<h3>How do we calculate original mass?</h3>
Original mass of any substance will be calculated as below for the decomposition reaction is:
N = N₀(1/2)ⁿ, where
N = remaining mass of krypton-81 = 1.675g
N₀ = original mass of krypton-81 = ?
n will be calculated as:
n = T/t, where
T = total time period = 458,000 years
t = half life time = 229,000 years
n = 458,000/229,000 = 2
Now putting all these values on the above equation, we get
N₀ = 1.675 / (1/2)²
N₀ = 6.70 g
Hence required mass is 6.70 g.
To know more about half life time, visit the below link:
brainly.com/question/2320811
