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dezoksy [38]
2 years ago
13

Harim placed 5mL of ethanol into a container that weighs 1 gram using a dropper. He already knew the density of ethanol is 0.78

g/mL.
What is the mass of the ethanol, not including the container?
Chemistry
1 answer:
Aleks04 [339]2 years ago
8 0

Answer:

there it is fella tried on ma own consciousness

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A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reac
svlad2 [7]
True true true true true
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3 years ago
6. If 0.500 mol NaN3 react, what mass in grams of nitrogen will result?
lions [1.4K]

Answer:

21 g of N₂ are produced by the decomposition

Explanation:

The reaction is: 2 NaN3 → 2 Na + 3 N2

2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.

According to stoichiometry, ratio is 2:3. Therefore we say,

2 moles of nitride can produce 3 moles of N₂

Then, 0.5 moles of NaN₃ will produce (0.5 . 3) / 2 = 0.75 moles of N₂

We convert the moles to mass, to find the answer

0.75 mol . 28 g / 1 mol = 21 g

7 0
2 years ago
The Heliocentric model is when the sun, planets, and stars are orbiting a stationary Earth.
Anarel [89]
False

A heliocentric is when the model is
representing the sun as the center
A geocentric says the earth is at the center of the universe
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2 years ago
Add them to your friend's list and have them support you along your Brainly journey. Just go to the profile of the person you’d
Makovka662 [10]

Answer:

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8 0
2 years ago
A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of
Firdavs [7]

Answer: 318 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 231 kPa

P_2 = final pressure of gas = 168 kPa

V_1 = initial volume of gas = 3.25 L

V_2 = final volume of gas = 4.35 L

T_1 = initial temperature of gas = 54^oC=273+54=327K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{231\times 3.25}{327}=\frac{168\times 4.35}{T_2}

T_2=318K

At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa

4 0
3 years ago
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