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FinnZ [79.3K]
3 years ago
12

3.

Chemistry
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

<h3>no it is not allowed</h3>

Explanation:

<h3>Liwis structure shows the elements symbol with dots thet represents valance electrons ; in second row elements their atomic number is 3 up to 10 , from Li up to Ne from their electron configuration their valance electron will be from 1 up to 8 respectivelly ,if lewis structure represents the element with it is symbol and dots that represents valance electron the second row elements cannot have more than an octet of valance electrons surrounding it.</h3>

<h3>I think it is help ful for you </h3>
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What are some things that could happen to you if you have an electrolyte imbalance?
Anestetic [448]

Answer:

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4 0
3 years ago
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The vapor pressure of ethanol is 1.00 × 102 mmHg at 34.90°C. What is its vapor pressure at 60.21°C? (ΔHvap for ethanol is 39.3 k
Delicious77 [7]

Answer:

The vapor pressure at 60.21°C is 327 mmHg.

Explanation:

Given the vapor pressure of ethanol at 34.90°C is 102 mmHg.

We need to find vapor pressure at 60.21°C.

The Clausius-Clapeyron equation is often used to find the vapor pressure of pure liquid.

ln(\frac{P_2}{P_1})=\frac{\Delta_{vap}H}{R}(\frac{1}{T_1}-\frac{1}{T_2})

We have given in the question

P_1=102\ mmHg

T_1=34.90\°\ C=34.90+273.15=308.05\ K\\T_2=60.21\°\ C=60.21+273.15=333.36\ K\\\Delta{vap}H=39.3 kJ/mol

And R is the Universal Gas Constant.

R=0.008 314 kJ/Kmol

ln(\frac{P_2}{102})=\frac{39.3}{0.008314}(\frac{1}{308.05}-\frac{1}{333.36})\\\\ln(\frac{P_2}{102})=4726.967(\frac{333.36-308.05}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{333.36\times308.05})\\\\ln(\frac{P_2}{102})=4726.967(\frac{25.31}{102691.548})\\\\ln(\frac{P_2}{102})=1.165

Taking inverse log both side we get,

\frac{P_2}{102}=e^{1.165}\\\\P_2=102\times 3.20\ mmHg\\P_2=327\ mmHg

8 0
3 years ago
The speed of a spaceship is going warp 7.58. What is the velocity of the spaceship in cm/min. Assume 1.00 warp = 2.5 times the s
grandymaker [24]

Answer : The velocity of the spaceship is, 3408.6\times 10^{10}cm/min

Solution :

As we are given that,

1.00\text{ wrap }=2.5\times \text{The speed of light}

The speed of a spaceship = 7.58 wraps

So, 7.58\text{ wrap }=7.58\times 2.5\times \text{The speed of light}

The speed of light = 2.9979\times 10^8m/s

Now put the value of speed of light in above expression, we get

So, 7.58\text{ wrap }=(7.58)\times (2.5)\times (2.9979\times 10^8m/s)=56.81\times 10^8m/s

The velocity of the spaceship = 56.81\times 10^8m/s

Now we have to convert the velocity of the spaceship m/s to cm/min.

Conversion :

(1 m = 100 cm)

(1 min = 60 sec)

The velocity of the spaceship = (56.81\times 10^8)\times 100\times 60cm/min=3408.6\times 10^{10}cm/min

Therefore, the velocity of the spaceship is, 3408.6\times 10^{10}cm/min

3 0
3 years ago
Help me number 1 pleasw
Vaselesa [24]
The answer to number 1 is D
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3 years ago
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Doubling the number of particles of gas in an inflated tire will double the pressure of the gas in the tire.
Mashutka [201]
True - more particles will be able to hit off the tire wall, therefore higher pressure
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3 years ago
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