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FinnZ [79.3K]
3 years ago
12

3.

Chemistry
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

<h3>no it is not allowed</h3>

Explanation:

<h3>Liwis structure shows the elements symbol with dots thet represents valance electrons ; in second row elements their atomic number is 3 up to 10 , from Li up to Ne from their electron configuration their valance electron will be from 1 up to 8 respectivelly ,if lewis structure represents the element with it is symbol and dots that represents valance electron the second row elements cannot have more than an octet of valance electrons surrounding it.</h3>

<h3>I think it is help ful for you </h3>
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PLEASE ITS A TEST !!!!!!!! HELPPP!!!!!
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In a carbohydrate, the ratio of hydrogen atoms to carbon atoms to oxygen atoms is:
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In a carbohydrate, the ratio of hydrogen atoms to carbon atoms to oxygen atoms is:4:6:1
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Convert 10kg⋅cm/s^2 to newtons
Solnce55 [7]

Answer:

one newton

Explanation:

tell me if it wrong

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Write the formula iron 11 bromide
vazorg [7]

Answer:

FeBr2

Explanation:

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5 0
2 years ago
molecules of i2 are produced by the reaction of 0.4321 mol of cucl2 according to the following equation. 2 cucl2 4 ki → 2 cui 4
Juli2301 [7.4K]

\: 1.237 \times 10^{23}   molecules \: of \:I _{2} \: are

are\: produced \: and \: 53.74 \: g \: of \: I _{2} \: are

produced from the reaction.

The overall balanced equation for the reaction is,

2CuCl_{2} +   KI→2CuI + 4KCl  + I_{2}

Number  \: of  \: moles  \: ofCuCl_{2}=0.4235 \: mol

2 \: moles \: of \: CuCl_{2} \: produce \: \: 1 \: mole \:

of \:  I_{2}.

2 \: mole \: of \: CuCl_{2}  = 1 \: mole \: of \:  I_{2}

1 \: mole \: of \: I_{2} \:  = 6.022 \times 10 ^{23}  \: molecules \: of  I_{2}

So, the number of molecules produced in the reaction of

I_{2} \: are

=  \frac{0.4235 \times 6.022 \times 10 ^{23} }{2 }

= 1.237 \times 10^{23}  \: molecules \:

1.237 \times 10^{23}  \: molecules \: of \: I_{2} \: are \:

produced from the reaction.

Mass  \: of \:   I _{2} \: produced \: are \: is ,

=  \frac{0.4235 \times 253.8}{2}

= 53.74 \: g

53.74 \: g \: of \:  I _{2} \: produced \: in \: the \:

reaction.

Therefore , \: 1.237 \times 10^{23}   molecules

of  \: I_{2} \: are\: produced \: and \: 53.74 \: g \: of

are produced in the reaction.

To know more about moles, refer to the below link:

brainly.com/question/26416088

#SPJ4

7 0
2 years ago
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