1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodka [1.7K]
2 years ago
15

Not sure what this is but last choice is 60 miles FIRST ANSWER GETS BRAINLIEST HEHEHE

Mathematics
2 answers:
goblinko [34]2 years ago
7 0
I think is B.
Hope this helps!!
disa [49]2 years ago
5 0

Answer: b

Step-by-step explanation:

You might be interested in
6415 divided 32 estimate
dsp73

Answer:

200

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can anybody help? Exponential Functions
lana [24]
................................................................................................
4 0
3 years ago
You usually buy a 16.5-ounce bottle of shampoo. There is a new bottle that says it gives you 30% more free.
Katarina [22]

Answer:

\frac{x-16.5}{16.5}=0.30

Hopefully, this is your desired setup. (I noticed the formula you have to fill in there.)

Have a good day.

Step-by-step explanation:

Hi.

You could use the percent change formula.

Since we know it is a percent increase then we will do new-old instead of old-new:

\frac{\text{new}-\text{old}}{\old}

x is the new amount of shampoo.

16.5 is the original amount (old) of shampoo.

The percent increase is 30%=0.30 .

So we have the following equation:

\frac{x-16.5}{16.5}=0.30

We could have found the equation like this:

16.5+16.5(0.30)=x

Subtract 16.5 on both sides:

16.5(0.30)=x-16.5

Divide both sides by 16.5:

0.30=\frac{x-16.5}{16.5}

By us of symmetric property of equality:

\frac{x-16.5}{16.5}=0.30

5 0
3 years ago
Read 2 more answers
A water hose had filled up 1/8 of a pool after 1/2 of an hour. At this rate, how many hours would it take to fill the pool.
GenaCL600 [577]
4 hours. You would multiply 1/8 by 1/2 and get 4.
8 0
3 years ago
Which of the following can be used to calculate the volume of water inside the fish bowl?
Lunna [17]

The volume of a sphere can be calculated as

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

r=\frac{AB}{2}=\frac{12}{2}=6

Let's put it into our equation

\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\  \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}

The problem says to use

\pi\approx\frac{22}{7}

Then

V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

8 0
1 year ago
Other questions:
  • If the zeros of a function are = 2 and = 7, what was the function? Could there be more than one answer?
    12·1 answer
  • What is 13 times 154
    10·2 answers
  • What is the answer to 5x-11=34
    8·2 answers
  • A cyclist rides at an average speed of 31 miles per hour. The cyclist’s speed, s, can differ from the average by as much as 8 mi
    14·2 answers
  • Joe wants to saw a wooden plank into 3/4 -meter pieces. The length of the wooden plank is 15/4meters. How many 3/4 -meter pieces
    8·1 answer
  • Ax - 8 = x + 2<br> If x = 2 on the equation above, what is the value of a?
    14·2 answers
  • a plastic box contains balls of different colors. among them, 18 balls were chosen. what does the number 18 represent?
    14·1 answer
  • What is the area of the circle that has a diameter of 12 ft?
    6·1 answer
  • ANSWER IT PLEASEEEEEEEEEE THANK YOU SO MUCH HAVE A NICE DAY !!!!
    10·1 answer
  • Need help with angle relationships worksheet
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!