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Sveta_85 [38]
3 years ago
7

What is the length of the rod as measured by this ruler?

Physics
1 answer:
Simora [160]3 years ago
7 0

2.2 CM is your answer

jfkanfnakcndbcnd

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Determine the projection (magnitude and sign), or component, of vector v1 along the direction of vector v2. Your answer could be
professor190 [17]

Answer:

- 1.07 ft

Explanation:

V1 = (-5, 7, 2)

V2 = (3, 1, 2)

Projection of v1 along v2, we use the following formula

=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}

So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4

The magnitude of vector V2 is given by

= \sqrt{3^{2}+1^{2}+2^{2}}=3.74

So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft

Thus, the projection of V1 along V2 is - 1.07 ft.

so we need to find the direction of v2

7 0
4 years ago
A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration
Eduardwww [97]
my answer is 1276.7 because I subtracted 88.3 miles and seconds from 1365 MI
7 0
3 years ago
An athlete runs four laps of a 400 m track. What is the athlete's total displacement?​
sasho [114]

Answer:

○ 0 \checkmark

Explanation:

Even if the athelete runs four laps of a 400 m track, its displacement will be 0 because the displacement is the shortest distance from its to final position. And, here the final and initial position is same since he comes to its initial position after covering certain distance. So, displacement is 0.

7 0
3 years ago
Chemical analysis of the oxygen isotopes in foraminifera shells allow scientists to create a climate record like the one shown h
IrinaK [193]
<span>Climatic changes can definitely influence changes in life forms.</span>
6 0
4 years ago
Read 2 more answers
A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.
trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = \sqrt{16^{2}+2^{2}} = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity =  \sqrt{18^{2}+14^{2}} = 22.804 m/s

KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J

According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

8 0
4 years ago
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