The overall efficiency of the conversion is 6.93%.
<h3>What is the overall efficiency?</h3>
We know that generation of electricity from radioactive fuels is one of the major ways by which we can generate electricity in many countries. Now the efficiency of each of the steps have been shown in the question;
- Conversion efficiency = 35%
- Transmission efficiency = 90%
- Light efficiency = 22%
Overall efficiency = (0.35 * 0.90 * 0.22) * 100 = 6.93%
The energy is obtained from;
6.7X10^13 J * 6.93/100
= 4.6 * 10^12 J
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Missing parts;
The atomic number of uranium-235 is 92, its half-life is 704 million years and the radioactive decay of l kg of 235U releases 6.7X10^13 J. Generally, radioactive material is considered safe after 10 half-lives.
Assume that a nuclear powerplant can convert energy from 235U into electricity with an efficiency of 35%, the electrical transmission lines operate at 90% efficiency, and flourescent lights operate at 22% efficiency.
1.) What is the overall efficiency of converting the energy of 235U into flourescent light?
2.) How much energy from 1 kg of 235U is converted into flourescent light?
