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erica [24]
4 years ago
11

Someone please help me it’s an assessment on Stochiometry

Chemistry
1 answer:
HACTEHA [7]4 years ago
6 0

Answer:

2) 0.3787moles

3) 198g

4) 7.658g

5)  12.26g

Explanation:

2)

2C6H6 + 9O2 -> 12CO2 + 6H20

Weight of a CO2 Mol 12+ 16x2 = 44g

In 100g number of moles = 100/44= 2.2727 Moles

Number of C6H6 2moles burned when creating 12 moles of CO2

Therefore 2.2727/12 x 2 = 0.3787

3)  

3H2SO4 + 2Al(OH)3 -> Al2(SO4)3 + 6H2O

H2O weight of a 1mol is = 2+16 = 18g

2moles of Al(OH)3 cerates 6 moles of water.

3moles of sulfuric creates 6 moles of water.

5.5moles Al(OH)3 reacts with 5.5 moles of sulfuric

Therefore number of water moles = 5.5/3 x 6 = 11moles

Weight water = 11 x 18 = 198g

4)  

Cu + 2AgNO3 -> 2Ag + Cu(NO3)2

1mol of Cu produces 2moles of silver

Ag = 107.86 g/Mol

Cu = 63.54 g/Mol

In 26g Ag number of moles = (26/107.86)/2 x 63.54 = 7.658g

5)

3K2CrO4 + 2AlPO4 -> 2K3PO4 + Al2(CrO4)3

K2CrO4 = 39x2 + 52 + 16x4 = 194g/Mol

Al2(CrO4)3 = 54 + 354 = 408g/Mol

3moles of K2CrO4 creates 1mol of Al2(CrO4)3

Therefore weight of the Al2(CrO4)3 produced by 17.5g potassium chromate

(17.5/194)/3 moles of Al2(CrO4)3 produced  = 0.03moles

Al2(CrO4)3 produced = 0.03 x 408 = 12.26g

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prohojiy [21]

Answer:

+523 kJ.

Explanation:

The following data will be used to calculate the average C-S bond energy in CS2(l).

S(s) ---> S(g)

ΔH = 223 kJ/mol

C(s) ---> C(g)

ΔH = 715 kJ/mol

Enthalpy of formation of CS2(l)

ΔH = 88 kJ/mol

CS2(l) ---> CS2(g)

ΔH = 27 kJ/mol

CS2(g) --> C(g) + 2S(g)

So we must construct it stepwise.

1: C(s) ---> C(g) ΔH = 715 kJ

2: 2S(s) ---> 2S(g) ΔH = 446 kJ

adding 1 + 2 = 3

ΔH = 715 + 446

= 1161 kJ

3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ

4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ

adding (reversed 3) from 4 = 5

ΔH = -1161 + 88

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5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ

6: CS2(l) ---> CS2(g) ΔH = 27 kJ

adding 5 + 6 = 7

ΔH = -1073 + 27

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7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ

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= -(-1046)/2

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8 0
3 years ago
Carbon disulfide, CS2, can be made from coke, C(s), and sulfur dioxide, SO2(g). C(s) + SO2(g) à CS2(s) + CO2(g) If the actual yi
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Answer:

450g of coke (C)

Explanation:

Step 1:

The balanced equation for the reaction is given below:

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Step 2:

Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C = 12g/mol

Mass of C from the balanced equation = 3 x 12 = 36g

Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3:

Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e

Xg of C = (36 x 950)/76

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3 years ago
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Answer:

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Explanation:

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The statement "According to Le Châtelier's principle, an increase in temperature will shift the equilibrium position toward the products in an endothermic reaction" is definitely true.

<h3>What is Le Châtelier's principle?</h3>

Le Châtelier's principle may be defined as transformations in the temperature, pressure, volume, or concentration of a system that will lead to observable and conflicting changes in the strategy in order to accomplish a refreshed equilibrium state.

According to Le Châtelier's principle, an increase in temperature generates the equilibrium to move in the direction of the product of the endothermic reaction, and the decrease in the temperature rationales the equilibrium to move in the direction of the product of the exothermic reaction.

Therefore, it is well described above.

To learn more about Le Châtelier's principle, refer to the link:

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