How many moles of cesium xenon heptafloride can be produced from the reaction 12 mol cesium Floride with 14 mol xenon hexaflorid
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In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol .
(a) For first order reaction, rate constant and half life time are related to each other as follows:
Thus, rate constant of the reaction is .
(b) Rate equation for first order reaction is as follows:
now, 75% of the compound is decomposed, if initial concentration is 100 then concentration at time t
will be 100-75=25.
Putting the values,
On rearranging,
Thus, time required for 75% decomposition is 21 min.
Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.
Solution : Given,
Density of solution = 1.25 g/ml
Molar mass of (solute) = 95.21 g/mole
3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.
The volume of solution = 1 L = 1000 ml
Mass of (solute) = 3.37 g
First we have to calculate the mass of solute.
Now we have to calculate the mass of solution.
Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g
Now we have to calculate the molality of the solution.
The molality of the solution is, 0.0381 mole/Kg.
Now we have to calculate the mass/mass percent.
The mass/mass percent is, 25.67 %
Now we have to calculate the mass/volume percent.
The mass/volume percent is, 32.086 %
Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.