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scoundrel [369]
2 years ago
9

Consider the first four terms of the sequence below.

Mathematics
1 answer:
tigry1 [53]2 years ago
8 0

Answer:

the answer is C.-1/128......

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What is the solution for the determinant?
Liono4ka [1.6K]
<span>The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.

The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.

= [ (1)(-3)] - [ (7)(0) ]
= -3 - 0
= -3

Therefore, the determinant is -3.

Hope this helps!</span>
4 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
If G is the midpoint of FH, FG= 14x + 25 and GH = 73- 2x, find FH
Alenkinab [10]
Given that G is the midpoint of FH, then:
FG=GH
hence;
14x+25=73-2x
solving for x we get:
14x+2x=73-25
16x=48
x=48/16
x=3
therefore the length FG=14x+25 will be:
14*3+25
=67
hence FH will be:
FH=67*2=134
4 0
3 years ago
Find the oth term of the geometric sequence 3, 15,75, ...
Zinaida [17]

Answer:

375

Step-by-step explanation:

hope this helps

4 0
3 years ago
NEED HELP EDU!! WILL GIVE BRAINLEIST!<br> which graph of the cube root function f(x)=^3 √x?
Luden [163]

Answer:

C. f(x)=\sqrt[3]{-x} -1

Step-by-step explanation:

Consider graph of the parent function (red curve in attached diagram)

g(x)=\sqrt[3]{x}

First, multiply it by -1 to get function

h(x)=-\sqrt[3]{x}

Then translate the graph of the function h(x) 1 unit down, then you'll get the function

f(x)=-\sqrt[3]{x} -1\\ \\ \text{or}\\ \\f(x)=\sqrt[3]{-x} -1

The graph of the function f(x) is represented by the blue curve in attached diagram

5 0
3 years ago
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