<span>The
value of the determinant of a 2x2 matrix is the product of the top-left
and bottom-right terms minus the product of the top-right and
bottom-left terms.
The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.
= [ (1)(-3)] - [ (7)(0) ]
= -3 - 0
= -3
Therefore, the determinant is -3.
Hope this helps!</span>
The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>
From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation

This gives

Evaluate the products

Evaluate the like terms

So, we have
f(x) = x²+ 2/3x - 1/9
Read more about quadratic equations at
brainly.com/question/1214333
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Given that G is the midpoint of FH, then:
FG=GH
hence;
14x+25=73-2x
solving for x we get:
14x+2x=73-25
16x=48
x=48/16
x=3
therefore the length FG=14x+25 will be:
14*3+25
=67
hence FH will be:
FH=67*2=134
Answer:
375
Step-by-step explanation:
hope this helps
Answer:
C. ![f(x)=\sqrt[3]{-x} -1](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B-x%7D%20-1)
Step-by-step explanation:
Consider graph of the parent function (red curve in attached diagram)
![g(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
First, multiply it by -1 to get function
![h(x)=-\sqrt[3]{x}](https://tex.z-dn.net/?f=h%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D)
Then translate the graph of the function h(x) 1 unit down, then you'll get the function
![f(x)=-\sqrt[3]{x} -1\\ \\ \text{or}\\ \\f(x)=\sqrt[3]{-x} -1](https://tex.z-dn.net/?f=f%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D%20-1%5C%5C%20%5C%5C%20%5Ctext%7Bor%7D%5C%5C%20%5C%5Cf%28x%29%3D%5Csqrt%5B3%5D%7B-x%7D%20-1)
The graph of the function f(x) is represented by the blue curve in attached diagram