Question

Find the value from the given photo​

Answer 1

Answer:

- $\frac{1}{3}$

Step-by-step explanation:

$\frac{2x-3y}{2x+3y}$ ← factor out y from each term on numerator/ denominator

= $\frac{y(2\frac{x}{y} -3)}{y(2\frac{x}{y} +3)}$

= $\frac{2(\frac{3}{4})-3 }{2(\frac{3}{4})+3 }$

= $\frac{\frac{3}{2}-3 }{\frac{3}{2}+3 }$

= $\frac{-\frac{3}{2} }{\frac{9}{2} }$

= - $\frac{3}{2}$ × $\frac{2}{9}$

= - $\frac{3}{9}$

= - $\frac{1}{3}$