All categories

2 years ago

Find the value from the given photo

Mathematics

1 answer:

kolbaska11 [484]2 years ago

5 0

Answer:

- $\frac{1}{3}$

Step-by-step explanation:

$\frac{2x-3y}{2x+3y}$ ← factor out y from each term on numerator/ denominator

= $\frac{y(2\frac{x}{y} -3)}{y(2\frac{x}{y} +3)}$

= $\frac{2(\frac{3}{4})-3 }{2(\frac{3}{4})+3 }$

= $\frac{\frac{3}{2}-3 }{\frac{3}{2}+3 }$

= $\frac{-\frac{3}{2} }{\frac{9}{2} }$

= - $\frac{3}{2}$ × $\frac{2}{9}$

= - $\frac{3}{9}$

= - $\frac{1}{3}$

You might be interested in

You earn $9 per hour. Which equation shows the relationship between the time worked in hours, t, and the money earned in dollars

luda_lava [24]

Answer:

m=9t

Step-by-step explanation:

to figure out how much money you earned, you have to multiply how long you worked by the amount you get paid

6 0

2 years ago

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

3 0

3 years ago

What is the median of 137 115 104 to 63 and 98

Romashka-Z-Leto [24]

Answer:

104

Step-by-step explanation:

put them from less to highest then find the middle number

5 0

2 years ago

4b - 7 - 15b + 3<br> Pls give full explanation I don't understand this stuff.

allsm [11]

Combine like terms so add 4b and 15b together and add 7 and 3 together and then the answer would be 19b-10

5 0

2 years ago

Read 2 more answers

(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard

AveGali [126]

Answer:

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.95=0.05$

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: $t_{n-1,\alpha/2}=t_{7,0.025}=2.365$

Sample mean : $\overline{x}=24.8\text{ hours}$

Standard deviation : $\sigma=3.2\text{ hours}$

The confidence interval for population means is given by :-

$\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}$

$24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)$

Hence, the 95% confidence interval, assuming the times are normally distributed.= (22.12, 27.48)

6 0

2 years ago

Find the value from the given photo​

Find the value from the given photo