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3 years ago

3/5 and 2/5 what is the common denomenator?

Mathematics

2 answers:

amid [387]3 years ago

5 0

Answer:

5 is their common denominator

Step-by-step explanation:

A common denominator is when both denominators are the same.

Zanzabum3 years ago

3 0

Answer:

5 is the common denominator of 3/5 and 2/5

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In order to get an. A in science,Jack must get at least 92% on his next test. If tbe test has 30 questions, what is the minimum

GaryK [48]

Answer:

Jack must Answer minimum 28 question correctly in order to get A in Science.

Step-by-step explanation:

Given:

Percentage required = 92%

Total Number of question = 30

We need to find the number of Question answer correctly.

Solution:

number of Question answer correctly be 'x'

So we can say that;

number of Question answer correctly divided by Total Number of question multiplied by 100 should be greater than or equal to percentage required.

framing in equation form we get;

$\frac{x}{30}\times 100\geq 92\\\\\frac{10x}{3}\geq 92$

Now Dividing both side by $\frac{3}{10}$ we get;

$\frac{3}{10}\times \frac{10x}{3}\geq 92\times \frac3{10}\\\\x\geq 27.2$

Hence Jack must Answer minimum 28 question correctly in order to get A in Science.

3 0

3 years ago

Suppose f(x) = x. Find the graph of f(x+1)

Hunter-Best [27]

Given:

f(x) = x

Therefore, if f(x) = x, than f(x + 1) = x + 1, for with an equal sign, what you do to one side, you do to the other.

Answer:

f(x + 1) = x + 1

hope this helps

8 0

3 years ago

Select the expressions that are equivalent to 8(6m).

Bas_tet [7]

$\textsf{Hey there!}$

$\text{Select the expressions that are equicalent to 8(6m)}\downarrow$

$\text{We DON'T have any like terms so we CAN'T pair them off!}$

$\mathsf{8(6m) \rightarrow 8 \times 6 \times \ m}\\\mathsf{8\times 6 = 48}}\\\mathsf{48\times\ m = 48m}\\\\\\\boxed{\boxed{\mathsf{Answer: \bf{48m}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

4 0

3 years ago

Help number 21 plzzz

PtichkaEL [24]

Answer:

B. C

Step-by-step explanation:

thats what I think it is

8 0

3 years ago

During a dig, an archaeological team starts at an elevation of −512 feet. At a rate of 234 feet per hour, the team digs deeper i

creativ13 [48]

Are you referring to this question?
During a dig, an archaeological team starts at an elevation of −5 1/2 feet. At a rate of 2 3/4 feet per hour, the team digs deeper into the surface for 3 1/2 hours. For the next 4 1/2 hours, the team digs at a rate of 1 5/12 feet per hour. Then the team quits for the day.
How many feet did the archaeological team dig after 3 1/2 hours?
<span>What was the team's elevation at the end of the day?
</span>
If so, then let us find out the elevation.

The rate of their dig is 2 3/4 ft per hr for 3 1/2 hours, then the total distance dug after 3 1/2 hours should be: 9 5/8 ft

Here’s how we get the total distance:

First, change mixed number into improper fraction and proceed to multiplication

2 3/4--> 11/4 and 3 1/2 becomes 7/2

Multiply.

11/4 x 7/2 = 77/8

Simplify 77/8--> 9 5/8 ft

Let us move on at the rate of 1 5/12 ft per hr for the next 4 1/2 hr,

Following the same procedure as above, the distance would be: 6 9/24 ft

Distance= 1 5/12 x 4 1/2

= 17/12 x 9/2

= 153/24

= 6 9/24 ft

Thus,to sum up everything, they have a total dug of:

9 5/8 + 6 9/24 = 9 15/24 + 6 9/24 = 16 ft

Then, their elevation on that day<span> is -5 1/2 - 16 = -21 1/2 ft</span>

5 0

4 years ago