Which point is coplanar with a, b and c in the diagram below

Mathematics

1 answer:

Gekata [30.6K]3 years ago

8 0

Answer:

D because it on the same plane as abc so it is a coplanar. also I got it right on my test.

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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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3 years ago

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(-1) to the power of an even number is +1.

(-1) to the power of an odd number is -1.

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Figure ABCD is a parallelogram.

STatiana [176]

The answer is 14 units

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What answee is it?? :))))

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Step-by-step explanation:

The answer is C

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We can also eliminate choice A, because 5 to the 3rd power isn't 15.

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The answer is ....1.237149 x 10^18

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