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Tom [10]
3 years ago
9

PLS HELP ASAP! GIVING BRAINLIST

Mathematics
1 answer:
Andrews [41]3 years ago
4 0

Answer:

f(x)=(3x+6)(x-2)

Step-by-step explanation:

(3x+6)

(x-2)

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7 0
3 years ago
A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 3 inches. The height of the cone is 18 inc
Bond [772]

The relationship is that two times the volume of cylinder is volume of cone

<em><u>Solution:</u></em>

Given that, cylinder and a cone have the same diameter: 8 inches

Diameter = 8 inches

Radius is diameter divided by 2

radius = \frac{diameter}{2}\\\\radius = \frac{8}{2} = 4

Radius = 4 inches

<u><em>Let us find the volume of cylinder and cone</em></u>

<u><em>Volume of cylinder:</em></u>

volume = \pi r^2 h

Radius = 4 inches

The height of the cylinder is 3 inches

height = 3 inches

Substituting the values, we get

volume = 3.14 \times 4^2 \times 3\\\\volume = 3.14 \times 16 \times 3\\\\volume = 150.72

Thus volume of cylinder is 150.72 cubic inches

<em><u>Volume of cone:</u></em>

volume = \frac{\pi r^2h}{3}

Radius = 4 inches

The height of the cone is 18 inches

height = 18 inches

Substituting the values, we get

volume = \frac{3.14 \times 4^2 \times 18}{3}\\\\volume = 3.14 \times 16 \times 6\\\\volume = 301.44

Thus volume of cone is 301.44 cubic inches

<em><u>What is the relationship between the volume of this cylinder and this cone?</u></em>

Volume of cylinder is 150.72 cubic inches

Volume of cone is 301.44 cubic inches

On observing the volume of cylinder and cone, we find that two times the volume of cylinder is volume of cone

2 \times \text{Volume of cylinder} = \text{Volume of cone}

2 \times 150.72 = 301.44\\\\301.44 = 301.44

Thus the relationship between the volume of this cylinder and this cone is that two times the volume of cylinder is volume of cone

5 0
4 years ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
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