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kumpel [21]
2 years ago
6

Elliot spent 3/7 of his money on some comics. He spent 1/4

Mathematics
1 answer:
QveST [7]2 years ago
3 0

Answer:

a) 3/7

b) $14

Step-by-step explanation:

let the total of his Money be x

on some comics = 3/7 of x

\frac{3}{7}  \times x \:  =  \frac{3x}{7}

remaining money = x - 3x/7

x -  \frac{3x}{7}  =  \frac{7x - 3x}{7}  =  \frac{4x}{7}

on a pack of cards = 1/4 of 4x/7

\frac{1}{4}  \times  \frac{4x}{7}  =  \frac{4x}{28}  =  \frac{x}{7}

a) left fraction = total money - all spent money

<em>note that</em>; all spent money = money spent on some comics and pack of cards

x - ( \frac{3x}{7} +   \frac{x}{7} )

x - ( \frac{3x  + x }{7} )

x -  \frac{4x}{7}  =  \frac{7x - 4x}{7}  =  \frac{3x}{7}

left fraction = 3/7 of the money

b) left money = 3x/7

but since left money is $6

therefore, $6 = 3x/7

multiply both sides by 7

6 \times 7 =  \frac{3x}{7}  \times 7

42= 3x

divide both sides by 3

x = 42/3

x = 14

total money = $14

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
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Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

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Step-by-step explanation:

Given

See attachment for class

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\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

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<em>See attachment for result of 1-VarStats</em>

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