Answer:
12 cm
Step-by-step explanation:
1. Consider right triangle MNK. In this triangle angle N is right and m∠M=60°, then m∠K=30°. Thus, this triangle is special 30°-60°-90° right triangle with legs MN and NK and hypotenuse MK=16 cm. The leg MN is opposite to the angle with measure of 30°, then this leg is half of the hypotenuse, MN=8 cm.
2. Consider right triangle MNH, where NH is the height of trapezoid drawn from the point N. In this triangle m∠M=60°, angle H is right, then m∠N=30°. Similarly, the leg MH is half of the hypotenuse MN, MH=4 cm.
3. Trapezoid MNOK is isosceles, because MN=OK=8 cm. This means that NO=MK-2MH=16-8=8 cm.
4. The midsegment of the trapezoid is

Answer:
Step-by-step explanation:Given Equation of line has slope m=-3/2
So the line passing through (4,6) has the same slope because both are parallel
From slope intercept form we have
y-y1=m(x-x1)
y-6=-3/2(x-4)
y-6=-3/2x +3/2(4)
y=-3/2x+12
2y=-3x+24
<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>3</u></em><em><u>r</u></em><em><u>d</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
Step-by-step explanation:
∆FGE ~ ∆ JKL
i.e, Angle FGE = angle JKL = 63°
and angle GEF = angle KLJ = 29°
also, angle GFE = angle KJL = 88°
so, the ∆FGE ~ ∆ JKL by AA property of similarity !!
• not other options because if we take corresponding angle they are not equal
For eg. for ∆ EFG ~ ∆ JKL
the angle EFG must be equal to angle JKL to be similar !!
but they are not equal !!
so, they are not similar !!
and such ,all other options except 3rd is wrong !!