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3 years ago

Factor 48m - 80n. 16mn(3m - 5n) 16(5n - 3m) 16(3m - 5n)

1 answer:

4 0

The correct answer for this would be the last option. The factors of 48m - 80n are 16(3m - 5n). If you try to solve this, the result would be 48m - 80n. 16 x 3m would be 48m and 16 times 5n would be 80n. Hope this is the answer that you are looking for.

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T' is (6, 6) what is the scale factor of the dilation

Colt1911 [192]

Is this all the information that you have

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2 years ago

For what value of x is PQ || BC? A 5 B. 6 C. 7 D. 8

Dahasolnce [82]

Answer:

C. 7

Step-by-step explanation:

$In\: \triangle ABC\\\overline{PQ} \parallel \overline {BC}.. (given) \\$

Therefore, by Basic Proportionality theorem:

$\frac{AP}{PB} = \frac{AQ}{QC} \\\\\therefore \frac{x}{x+7} = \frac{x-3}{x+1} \\\\ \therefore \: \frac{x - x - 7}{x + 7} = \frac{x - 3 - x - 1}{x + 1} \\ (by \: dividendo) \\ \\ \frac{ - 7}{x + 7} = \frac{ - 4}{x + 1} \\ \\ \frac{7}{x + 7} = \frac{4}{x + 1} \\ \\ 7x + 7 = 4x + 28 \\ \\ 7x - 4x = 28 - 7 \\ \\ 3x = 21 \\ \\ x = \frac{21}{3} \\ \\ \huge \red{ \boxed{ x = 7}}$

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2 years ago

Two positive improper fractions are multiplied. Is the product sometimes, always or never less than 1. explain

melisa1 [442]

Given situation : 2 improper fraction is multiplied. Now is the product always more than than 1?
Yes, the product is always more than 1. Because take note that in improper fraction, the numerator is always higher compare to the denominator of the given fraction. That means when you divide the numerator from the denominator, the answer would always be more than 1.
Example:
=> 5 / 4 x 4 / 2
=> 20 / 8 or equals to 5/2
now divide
=> 5 / 2
=> 2 1/2

6 0

2 years ago

A new battery's voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries wil

klio [65]

Answer:

The probability that you test exactly 4 batteries is 0.0243.

Step-by-step explanation:

We are given that a new battery's voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries will be independently selected and tested until two acceptable ones have been found.

Suppose that 90% of all batteries have acceptable voltages.

Let the probability that batteries have acceptable voltages = P(A) = 0.90

So, the probability that batteries have unacceptable voltages = P(U) = 1 - P(A) = 1 - 0.90 = 0.10

Now, the probability that you test exactly 4 batteries is given by the three cases. Firstly, note that batteries will be tested until two acceptable ones have been found.

So, the cases are = P(AUUA) + P(UAUA) + P(UUAA)

This means that we have tested 4 batteries until we get two acceptable batteries.

So, required probability = (0.90 $\times$ 0.10 $\times$ 0.10 $\times$ 0.90) + (0.10 $\times$ 0.90 $\times$ 0.10 $\times$ 0.90) + (0.10 $\times$ 0.10 $\times$ 0.90 $\times$ 0.90)

= 0.0081 + 0.0081 + 0.0081 = 0.0243

Hence, the probability that you test exactly 4 batteries is 0.0243.

3 0

2 years ago

Whats 9+10? how did you come up with your answer??

slamgirl [31]

Answer:

9 + 10 = 19

I got my answer by by adding 9 and 10 together.

Step-by-step explanation:

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2 years ago

Read 2 more answers