The domain of a function is the set of input or argument values for which the function is real and defined.
So, for the given function to be defined, we need to find the possible values for which the values of x makes the square root to be positive.
That is;
-9 -5x ≥ 0
Now, let's solve for x
Add 9 to both-side of the equation
-5x ≥ 9
Divide both-side by -5
x ≤ -9/5
Therefore, the domain of the function can be represented in interval notation as: ( - ∞ , -9/5]
I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,




So, 

So, 
Hope this helps you!
3x - 1 = 3x + 1
subtract 3x from both sides to get (-1 = 1). This is a false statement so it is: CONTRADICTION
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4x - 11 = 7
add 11 to both sides and then divide both sides by 4 to get
. This statement is true only when x =
so it is: CONDITIONAL
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2 - 8x = 2 - 8x
add 8x to both sides to get (2 = 2). This is a true statement so it is: IDENTITY
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x + 1 = -x + 4
add x to both sides, subtract 1 from both sides, and divide both sides by 2 to get
. This statement is true only when x =
so it is: CONDITIONAL
Answer: B, A, C, A