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Galina-37 [17]
3 years ago
7

Pls help me and i mark u as brainlist

Mathematics
1 answer:
raketka [301]3 years ago
6 0

Answer:

the fourth one, H

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Can anyone show me how to divide 931/7
Inessa [10]
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
 Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.

7 0
3 years ago
Which is the correct graph for *<br> y&gt; 2х – 4<br> А)<br> ОА<br> Ос
user100 [1]

Answer:

your answer would be OA

Step-by-step explanation:

8 0
3 years ago
Assume lim f(x)-6 and lim g(x)-9. Compute the following limit and state the limit laws used to justify the computation.
emmasim [6.3K]

Answer:

4

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

lim( f(x)  + g(x)) =lim f(x) + lim g(x)

lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

lim( f(x)/g(x)) =lim f(x) / lim g(x) if  lim g(x) is not equal to zero.

lim( f(x))^2 = (lim f(x) )^2

lim  square root( f(x)) = square root(lim f(x) )

\lim_{n \to 3} g(x)  = 9\\\\\lim_{n \to 3} f(x)  = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}

= 4

4 0
3 years ago
Complete the square and write the quadratic equation in vertex form please show steps
nasty-shy [4]

Answer:

Square: (x-10)^{2} -68

Vertex: (10,-68)

Step-by-step explanation:

5 0
2 years ago
Find the value for x and y for the triangle. Show work.
makkiz [27]

Step-by-step explanation:

done

.......................

7 0
3 years ago
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