<span> In order to bisect an angle is the normal way by joining the vertex of the lines with the double arc that is created
i hope this helps you</span>
Answer: last option
Step-by-step explanation:
The formula to find the Discriminant is:

Given the quadratic equation
, you can identify that:

Now, you can substitute values into the formula
, then:

As the Discriminant is greater than 0 (
), then the quadratic equation
has two distinct real solutions.
Using transformation rules, it is found that the correct option is:
No, A'C'B' is located at A(-1,1), C'(-3,4) and B'(-5,1).
--------------------
- The transformation rule for a reflection over the x-axis is

- The transformation rule for a rotation of 180º is

- After the reflection over the x-axis:

- Taking the reflection, and rotating:
. - Not the same rule, that is,
, so it would not map figure onto itself. - A(1,1) would be mapped to A(-1,1), for example, thus, the correct option is:
No, A'C'B' is located at A(-1,1), C'(-3,4) and B'(-5,1).
A similar problem is given at brainly.com/question/10547006
Answer:
Answer: 10.875
Step-by-step explanation:
Let the short side be x.
Then the long side is 3x.
There are two opposite sides of each length, so the perimeter is
3x + 3x + x + x = 8x
The perimeter is 29, so we get the equation
8x = 29
Solve for x by dividing both sides by 8.
x = 29/8
x = 3.625
The longer side is 3x.
3x = 3(3.625) = 10.875
Answer: 10.875
Answer:
yes it is the 10th term in the series
Step-by-step explanation:
The nth term of a geometric sequence is
= a₁ 
where a₁ is the first term and r the common ratio
Here a₁ = 7 and r =
=
= 2 , then
= 7 
Equate
to 3584 and solve for n
7
= 3584 ( divide both sides by 7 )
= 512 , that is
=
Since the bases on both sides are equal, both 2 , then equate the exponents
n - 1 = 9 ( add 1 to both sides )
n = 10
3584 is the 10th term in the series