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lubasha [3.4K]
3 years ago
7

Angle EFG has a measure of 133º. Triangle EFG is rotated 180° counterclockwise about point F to create triangle E'F'G'.

Mathematics
2 answers:
alekssr [168]3 years ago
7 0

Answer:313^{\circ}

Step-by-step explanation:

Given

\angle {EFG}=133^{\circ }

When rotated 180 degree clockwise gives E'F'G' which measures

\angle E'F'G'=180^{\circ}+133^{\circ}=313^{\circ}

This can be explained by the below-given digram  

sergiy2304 [10]3 years ago
5 0

Answer:

the answer is C

Step-by-step explanation:

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I think the answer is B.
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4 0
3 years ago
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What is the solution to the equation
Firdavs [7]
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5 0
2 years ago
On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapid
Dima020 [189]

Answer:

L(t) = 4600\bigg(\dfrac{6}{7}\bigg)^{\frac{t}{2.4}}  

Step-by-step explanation:

We are given the following in the question:

Number of locusts on first day = 4600

Gain in locust population every 2.4 days =

\dfrac{6}{7}

Thus, we can write the following function to model locust population in t days.

L(t) = 4600\bigg(\dfrac{6}{7}\bigg)^{\frac{t}{2.4}}

is the required function.

L(t) is a dependent function on t, L(t) is locusts population and t is amount of time in days.

4 0
3 years ago
Consider it this cone with a diameter of 19 cm use the drop-down menus to describe the con measurements
MAVERICK [17]

Answer:

1) Radius of the cone = 9.5 cm

2) BA = 90.25 π cm²

3) SA = 384.7 π cm²

Step-by-step explanation:

1) Radius of the cone = 9.5 cm

2) Base Area of the cone = \pi r^2

BA = (π)(9.5)²

BA = 90.25 π cm²

3) Surface Area of Cone = \pi r(r+\sqrt{h^2+r^2)}

SA = π(9.5)(9.5 + √(29.5)²+(9.5)²)

SA = 9.5π(9.5 + 31)

SA = 9.5π(40.5)

SA = 384.7 π cm²

3 0
4 years ago
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