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Bas_tet [7]
3 years ago
12

If someone was born in 2018 September 12th how old will they be in 2082?

Mathematics
2 answers:
Margaret [11]3 years ago
7 0

Answer: 64 years old

Step-by-step explanation:You subtract 2082 by 2018 to get the sum of 64

ikadub [295]3 years ago
7 0

Answer:

64/63

Step-by-step explanation:

It depends on what day it is in 2082 however the calculation should be simple...

2082-2018=64

If it is before September 12th in 2082, then they would be 63 because their 64th birthday would be on September 12th!

Hope this helps!

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Ten less than a number is three more than six times the number.
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Write it as an equation:

X - 10 = 6x + 3

Now solve for x:

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x-13 = 6x

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Solve the system by finding the determinants and using Cramer's Rule:<br> 2x - y = 4<br> 3x + y = 1
Ahat [919]

Answer:

<em>(1, - 2) </em>

Step-by-step explanation:

2x - y = 4

3x + y = 1

A = \left[\begin{array}{cc}2&-1\\3&1\end{array}\right] = 2(1) - 3( - 1) =2 + 3 = 5

A_{x} = \left[\begin{array}{cc}4&-1\\1&1\end{array}\right] = 4(1) - 1(- 1) = 4 + 1 = 5

A_{y} = \left[\begin{array}{cc}2&4\\3&1\end{array}\right] = 2(1) - 4(3) = 2 - 12 = - 10

<em>x </em>= \frac{A_{x} }{A} =<em> 1</em>

<em>y </em>= \frac{A_{y} }{A} = <em>- 2</em>

<em>(1, - 2)</em>

5 0
2 years ago
a model of a car is amde to a scale of 1:40. the volume of the model is 45cm^3. calcualte the volume of the car. give your answe
spin [16.1K]

The volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

<h3>Scale modelling</h3>

Given the scale factor that model of a car is amde to a scale of 1:40, Giving that the model as 45cm^3, this means that;

1 = 45cm^2

Determine the volume of the car

40 = x

Find the ratio

1/40 = 45/x

x = 40*45

x = 1800cm^3

x = 0.0018m^3

Hence the volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

Learn more on scale factor here; brainly.com/question/25722260

#SPJ1

6 0
2 years ago
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