Evaluate the expression if a = 3, b = 5, and c = 6. c^2 + 3a × b
1 answer:
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Answer:
a)0.08 , b)0.4 , C) i)0.84 , ii)0.56
Step-by-step explanation:
Given data
P(A) = professor arrives on time
P(A) = 0.8
P(B) = Student aarive on time
P(B) = 0.6
According to the question A & B are Independent
P(A∩B) = P(A) . P(B)
Therefore
&
is also independent
= 1-0.8 = 0.2
= 1-0.6 = 0.4
part a)
Probability of both student and the professor are late
P(A'∩B') = P(A') . P(B') (only for independent cases)
= 0.2 x 0.4
= 0.08
Part b)
The probability that the student is late given that the professor is on time
=
=
= 0.4
Part c)
Assume the events are not independent
Given Data
P = 0.4
= = 0.4
= 0.4 x P
= 0.4 x 0.4 = 0.16
= 0.16
i)
The probability that at least one of them is on time
= 1-
= 1 - 0.16 = 0.84
ii)The probability that they are both on time
P = 1 -
= 1 -
= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56
Answer:
OPTION D
Step-by-step explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have
Here, is the domain and
is the co-doamin.
Therefore,
Now, OPTION A:
Substitute x = 4. We get f(x) = 3 18.
So, OPTION A is rejected.
Similarly, OPTION B:
Substitute x = 4. We get f(4) = 22 18.
It is rejected as well.
Now, for OPTION C:
Substitute x = 4. We get f(4) = -3 18.
So, OPTION C is also rejected.
OPTION D:
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.
Answer:
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