Question

Choose the SYSTEMS option.

Answer 1

Answer:

Object 1.

Explanation:

Given that,

Force applied = 100 N

The spring constant of object 1 = 100 N/m

The spring constant of object 2 = 200 N/m

Using Hooke's law, we find the force applied on the object to stretch.

For object 1,

F₁ = k₁x₁

$x_1=\dfrac{F_1}{k_1}\\\\x_1=\dfrac{100}{100}\\\\=1\ m$

For object 2,

F₂ = k₂x₂

$x_2=\dfrac{F_2}{k_2}\\\\x_2=\dfrac{100}{200}\\=0.5\ m$

Object 1 stretches 1 m and object 2 stretches 0.5 m. Hence, object 1 stretches furthur.