Answer:
The block will not move.
Explanation:
We'll begin by calculating the frictional force. This can be obtained as follow:
Coefficient of friction (µ) = 0.6
Mass of block (m) = 3 Kg
Acceleration due to gravity (g) = 10 m/s²
Normal reaction (R) = mg = 3 × 10 = 30 N
Frictional force (Fբ) =?
Fբ = µR
Fբ = 0.6 × 30
Fբ = 18 N
From the calculations made above, the frictional force of the block is 18 N. Since the frictional force (i.e 18 N) is bigger than the force applied (i.e 14 N), the block will not move.
Answer:

Explanation:
Given,
Width of rectangular tank, b = 1 m
Length of the tank, l = 2 m
height of the tank, d = 1.5 m
Depth of gasoline on the tank, h = 1 m


The differential form with the acceleration


acceleration in z-direction = 0 m/s²
g = 9.8 m/s²
a_y is the horizontal acceleration of the gasoline.



Hence, Horizontal acceleration of the gasoline before gasoline would spill is equal to 4.9 m/s²
With its apparent magnitude
Answer:
The net gravitational force on the mass is 
Explanation:
We have by Newton's law of gravity the force of attraction between masses 

Applying vales we get
Force of attraction between 135 kg mass and 38 kg mass is

Force of attraction between 435 kg mass and 38 kg mass is

Thus the net force on mass 38.0 kg is 
Answer:
The answer is "
"
Explanation:
Given:

Using formula:

= system initial and final linear momentum.
= system original and final linear pace.
= original weight of the car freight.
= car's maximum weight
