Question

To navigate, a porpoise emits a sound wave that has a wavelength of 3.3 cm. The speed at which the wave travels in seawater is 1522 m/s. Find the period of the wave.

Answer 1

Answer:

$2.2\times 10^{-5} s$

Explanation:

We are given that  

The wavelength of sound wave=$\lambda=3.3 cm=3.3\times 10^{-2}m/s$

1 cm/s=$10^{-2}m/s$

Speed of sound wave,v=$1522 m/s$

We have to find the period of the wave.

We know that

Frequency=$\nu=\frac{v}{\lambda}$

Using the formula

Frequency =$\frac{1522}{3.3\times 10^{-2}}=4.6\times 10^{4}$ Hz

Time period=$\frac{1}{4.6\times 10^4}=0.22\times 10^{-4}\times \frac{10}{10^1}=2.2\times 10^{-4-1}=2.2\times 10^{-5}s$

Using identity:$\frac{a^x}{a^y}=a^{x-y}$

Hence, the time period of the wave=$2.2\times 10^{-5} s$