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3 years ago

How is the acceleration of an object in uniform circular motion constant?

Physics

2 answers:

nevsk [136]3 years ago

5 0

In both magnitude and direction since acceleration is a vector quantity

STALIN [3.7K]3 years ago

5 0

Answer:

C. in both magnitude and direction

Explanation:

Circular motion is the movement of a body rotating around an axis along a circular path of constant radius. This movement can be uniform, if the speed of rotation is constant, or varied, if its speed changes over time. When an object moves in a circular motion, the speed is constant in magnitude and direction.

The circular movement occurs when a force of constant modulus is applied in a direction perpendicular to the speed of a piece of furniture, so that the modulus of this velocity remains constant, changing only its direction and its direction. The force applied in this case is called the centripetal force.

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IrinaK [193]

Answer:

Explanation:

v= s/t

V =90m/5s

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3 years ago

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near the center o

MrRa [10]

Answer:

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Explanation:

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L = Length of wire = 55 cm

N = Number of turns = 4000

I = Current

Magnetic field is given by

$B=\dfrac{\mu_0NI}{L}\\\Rightarrow I=\dfrac{BL}{\mu_0N}\\\Rightarrow I=\dfrac{0.17\times 0.55}{4\pi \times 10^{-7}\times 4000}\\\Rightarrow I=18.6012339739\ A$

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3 years ago

The ceiling of your lecture hall is probably covered with acoustic tile, which has small holes separated by about 5.9 mm. Using

timurjin [86]

Answer:

45.88297 m

Violet

Explanation:

x = Gap between holes = 5.9 mm

$\lambda$ = Wavelength = 527 nm

D = Diameter of eye = 5 mm

L= Distance of observer from holes

From Rayleigh criteria we have the relation

$\frac{x}{L}=1.22\frac{\lambda}{D}\\\Rightarrow L=\frac{xD}{1.22\lambda}\\\Rightarrow L=\frac{5.9\times 10^{-3}\times 5\times 10^{-3}}{1.22\times 527\times 10^{-9}}\\\Rightarrow L=45.88297\ m$

A person could be 45.88297 m from the tile and still resolve the holes

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3 years ago

A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t

spin [16.1K]

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

$f = f_{0}\frac{v + v_{o}}{v - v_{s}}$