Answer:
Explanation:
Given that,
The length of tension wire is 10m
L = 10m
It caries a current of 10A
I = 10A
The current is perpendicular to the magnetic field
B = 5.5 × x10⁻⁵ T.
Then, θ = 90°
The magnetic force that act on the line is?
F = i(L × B)
L × B = LB Sinθ
Where
I is the current
L is the length of the wire
B is the magnetic field
θ is the angle between the field and the direction of the length.
Then,
F = I × L × B × Sinθ
F = 10 × 10 × 5.5 × x10⁻⁵ × Sin 90
F = 5.5 × x10⁻³ N
Then, the magnetic force experience on the line is 5.5 × x10⁻³N
Speed = (distance) / (time)
Speed = (100 mi/2 hr)
Multiply by a fraction equal to 1 :
Speed = (100 mi/2 hr) x (1 hr/60 min)
Speed = (100 x 1 / 2 x 60) (mi-hr/hr-min)
Speed = (100 / 120) (mi / min)
Speed = 5/6 mi/min
<em>Speed = 0.833... mi/min</em>
The net torque exerted by the children on the branch of the tree is 1382 N-m.
The torque exert by the kids is calculated as
T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°
T=1382 N-m
Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.
Answer: 10.048m/s
Explanation:
We know that the radius is r = 4.0m
And for rotating things, the tangential velocity (or the velocity of the end of the centrifuge arm) can be calculated as:
v = r*w
The period is T = 2.5s,
This means that if sin(w*t) describes this situation, we have that:
sin(w*t) = sin(w*(t + T))
and we know that:
sin(w*0) = 0
sin(w*(0 + T)) = Sin(w*T) = 0
this means that w*T = 2*pi
w = 2*pi/T = 2*pi/2.5s = (2*3.14)/2.5 s = 2.512 hz
Then the velocity can be calculated as
v = r*w = 4.0m*2.512hz = 10.048m/s
Answer:
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