All categories

3 years ago

How is the acceleration of an object in uniform circular motion constant?

Physics

2 answers:

nevsk [136]3 years ago

5 0

In both magnitude and direction since acceleration is a vector quantity

STALIN [3.7K]3 years ago

5 0

Answer:

C. in both magnitude and direction

Explanation:

Circular motion is the movement of a body rotating around an axis along a circular path of constant radius. This movement can be uniform, if the speed of rotation is constant, or varied, if its speed changes over time. When an object moves in a circular motion, the speed is constant in magnitude and direction.

The circular movement occurs when a force of constant modulus is applied in a direction perpendicular to the speed of a piece of furniture, so that the modulus of this velocity remains constant, changing only its direction and its direction. The force applied in this case is called the centripetal force.

You might be interested in

what is the mass of a pure platinum disk with a volume of 113 cm3? the density of platinum is 21.4 g/cm3

Oduvanchick [21]

V=m×d
m=v/d
m=113/21.4
m=5.28g

6 0

3 years ago

Read 2 more answers

Exoplanets (planets outside our solar system) are an active area of modern research. Suppose astronomers find such a planet that

Leno4ka [110]

Answer:

8.829 m/s²

Explanation:

M = Mass of Earth

m = Mass of Exoplanet

$g_e$ = Acceleration due to gravity on Earth = 9.81 m/s²

g = Acceleration due to gravity on Exoplanet

$m=M-0.1M\\\Rightarrow m=0.9M$

$g_e=G\frac{M}{r^2}$

$g=G\frac{0.9M}{r^2}$

Dividing the equations we get

$\frac{g}{g_e}=\frac{G\frac{0.9M}{r^2}}{G\frac{M}{r^2}}\\\Rightarrow \frac{g}{g_e}=0.9\\\Rightarrow g=0.9g_e\\\Rightarrow g=0.9\times 9.81\\\Rightarrow g=8.829\ m/s^2$

Acceleration due to gravity on the surface of the Exoplanet is 8.829 m/s²

3 0

3 years ago

Ted is a high school student. He is very good at math, but he is not a very good English student. He likes all of his teachers;

scoray [572]

I think the correct answer is

D) Ted associated being asked a question with embarrassment.

Glad I could help, and good luck!

AnonymousGiantsFan

3 0

3 years ago

Read 2 more answers

You would like a pendulum that swings back and forth once every 2 seconds, but the one you have swings once every 1.9 seconds. W

patriot [66]

Your pendulum does a complete swing in 1.9 seconds. You want to SLOW IT DOWN so it takes 2.0 seconds.

Longer pendulums swing slower.

You need to <em>make your pendulum slightly longer</em>.

If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom. You can add weight or cut some off, and it won't change the speed a bit.

6 0

3 years ago

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT include

Kaylis [27]

The electric filed in V/m is 1.58 * 10^6 V/m

<h3>What is the electric field?</h3>

We know that the electric field is obtained as the ratio of the voltage to the distance that separates the plates.

Thus;

E = V/d

E = electric field

V = voltage

d = distance of separation

E = 24 * 10^3 V/1.52 * 10^-2 m

E = 1.58 * 10^6 V/m

Learn more about electric field :brainly.com/question/8971780

#SPJ1

7 0

2 years ago